the overall equation for the conversation of pyruvate to acetyl COA is as below
CH3COO-COO- + NAD+ + HS-COA = ch3-COO-S -COA +NADH +CO2
The oxidation of pyruvate led to a conversation of NAD+ to NADH and produces acetyl COA and CO2
The partial pressure is the amount of linguistic compound there is which makes the lagitude of the element 64.663
G to dkg is 1 place to the right, move the decimal point 1 place to the left
<span>225 g = 22.5 dkg
C is the answer</span>
This is true do to all the other particules around
To find moles in this sample, you would divide grams by molar mass of ethyl alcohol
(18.0g)/(46.07g/mol) = 0.391mol C2H6O
