Solve this system of linear equations.

Mathematics

1 answer:

KonstantinChe [14]3 years ago

6 0

Answer:

(-8,-6)

Step-by-step explanation:

You add the equations together, the 2y and -2y cancel out. You isolate x, then plug the answer you get for x from that into one of the equations. The amount you get for y is the y-coordinate and the amount you had for x is the x-coordinate. To check, try putting the y value into the equation you didn't plug the x into before. If you get the same x value as you had before, it means it's correct, I think.

You might be interested in

What's the answer? I need it please help me !!

Softa [21]

I believe this is J with a radius of 6

the formula for circumference is 2(pi)r so i just took the 12(pi) and divided it by 2, which left me with 6(pi), meaning that 6 would be the "r" in the situation

6 0

3 years ago

Prove the following identities.<br> cos(3pi/s+x)=sinx

kari74 [83]

$\cos \left(\frac{3\pi}{2}-x \right)=\sin x \\ \\ =\cos \left(\frac{3\pi}{2} \right)\cos x -\sin \left(\frac{3\pi}{2} \right) \sin x \\ \\ =0\cos x -(-1)(\sin x) \\ \\ =\sin x$