Answer:
C would be your rotaions
Step-by-step explanation:
if you compare the two graphs you can tell that the shape rotated on one fixated point, if that makes sense.
Answer:
B
Step-by-step explanation:
12x² - 157x - 40
Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term
product = 12 × - 40 = - 480 and sum = - 157
The factors are + 3 and - 160
Use these factors to split the x- term
12x² + 3x - 160x - 40 ( factor the first/second and third/fourth terms
= 3x(4x + 1) - 40(4x + 1) ← factor out (4x + 1) from each term
= (4x + 1)(3x - 40) ← in factored form → B
I think
it’s a uhhhh , i think it’s a carrot
![\bf \begin{array}{llll} &[(-6,2),(2,3),(1,1),(-7,2),(4,2)]\\\\ inverse& [(2,-6),(3,2),(1,1),(2,-7),(2,4)] \end{array} \\\\\\ \textit{is the original a one-to-one?}\qquad \stackrel{rep eated~y-values}{(-6,\stackrel{\downarrow }{2}),(2,3),(1,1),(-7,\stackrel{\downarrow }{2}),(4,\stackrel{\downarrow }{2})}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0A%26%5B%28-6%2C2%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C2%29%2C%284%2C2%29%5D%5C%5C%5C%5C%0Ainverse%26%20%5B%282%2C-6%29%2C%283%2C2%29%2C%281%2C1%29%2C%282%2C-7%29%2C%282%2C4%29%5D%0A%5Cend%7Barray%7D%0A%5C%5C%5C%5C%5C%5C%0A%5Ctextit%7Bis%20the%20original%20a%20one-to-one%3F%7D%5Cqquad%20%5Cstackrel%7Brep%20eated~y-values%7D%7B%28-6%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%282%2C3%29%2C%281%2C1%29%2C%28-7%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%2C%284%2C%5Cstackrel%7B%5Cdownarrow%20%7D%7B2%7D%29%7D)
notice, the inverse set is just, the same set with the x,y turned to y,x, backwards.
is it a one-to-one? well, for a set to be a one-to-one, it must not have any x-repeats, that is, the value of the first in the pairs must not repeat, and it also must not have any y-repeats, namely the value of the second in the pairs must not repeat.
