All categories

4 years ago

Pls help I’m being timed and I don’t understand a bit.

Mathematics

1 answer:

luda_lava [24]4 years ago

3 0

Jus divide Man U jus gotta divide Man U jus gotta divide

You might be interested in

Timothy is repairing a picture frame. He will need 5 pieces of wood, each measuring foot in length. He is going to cut the 5 pie

tekilochka [14]

The answer is 16 becuase of math

5 0

3 years ago

Read 2 more answers

(Score for Question 1: of 5 points)

Inga [223]

Answer:

jdjdjdbdjdjdjzjdjdjdbdjdjdjzjdjdjdbdjdjdjz

8 0

3 years ago

If the endpoints of ST are S (1,4) and T (5,2) then the midpoint is in Quadrant IV?

irina [24]

It is false that the midpoint is in quadrant IV

<h3>How to determine the midpoint location?</h3>

The endpoints are given as:

S (1,4) and T (5,2

The midpoint is

(x, y) = 0.5 *(x1 + x2, y1 + y2)

So, we have:

(x, y) = 0.5 *(1 + 5, 4 + 2)

Evaluate the expression

(x, y) = (3, 3)

The point (3, 3) is located in the first quadrant

Hence, it is false that the midpoint is in quadrant IV

Read more about quadrants at:

brainly.com/question/7196312

#SPJ1

6 0

2 years ago

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$

=> $P( X \ge 1) = 1 - P( X =0 ) > 0.95$

=> $P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95$

=> $1 - [1 * 1* (0.85)^{n}] > 0.95$

=> $[(0.85)^{n}] > 0.05$

taking natural log of both sides

$n = \frac{ln(0.05)}{ln(0.85)}$

=> $n = 19$

3 0

3 years ago

Write 2350 million in standard form

AleksAgata [21]

we know that

<u>Standard Form</u> is also known as Scientific Notation, is a method of writing numbers that accommodates value excessively large or small to be suitably written in Standard Decimal Notation

in this problem we have

$2,350\ million$