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kenny6666 [7]
3 years ago
12

In this triangle, side AT = 24. Please give the value for the sine, cosine, and tangent for this diagram (Which is the marked an

gle?). Give the value as a ratio ONLY. Make sure all ratios are in the lowest form.
Be sure to explain IN WRITING how you find sine, cosine, and tangent! If you are not sure, check the directions in this problem!

Question 1 options:

Mathematics
1 answer:
sashaice [31]3 years ago
5 0
The value  of the sine, cosine and tangent of the figure will be found as follows:
a] Sine
sin x=(opposite)/(hypotenuse)
opposite=7
hypotenuse=25
thus:
sin x=  7/25  

 b] Cosine
cos x=adjacent/hypotensue
adjacent=24
hypotenuse=25
cos x=24/25

Tangent
Tan x=opposite/adajcent
opposite=7
adjacent=24
thus
tan x=7/24

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Lelechka [254]
So sorry idek algebra 1
3 0
3 years ago
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Solve for x 4.72 = 3.25 + x
Anna [14]
Flip the situation:
X + 3.25 = 4.72

Subtract 3.25 from both sides
X + 3.25 - 3.25 = 4.72 - 3.25

X = 1.47
3 0
3 years ago
) Today there is a discount of $10 off a purchase of 5 or more concert tickets.
antiseptic1488 [7]

Answer:

Tickets * cost - 10

Step-by-step explanation:

5*cost-10

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3 years ago
A bicycle lock has a four-digit code. The possible digits, 0 What is the probability that the lock code will begin with
nika2105 [10]

Answer:

0.1-0.6

Step-by-step explanation:

First let's find the number of the elements in the sample space, that is the total number of codes that can be produced.

The first digit is any of {0, 1, 2...,9}, that is 10 possibilities

the second digit is any of the remaining 9, after having picked one. 

and so on...

so in total there are 10*9*8*7 = 5040 codes.

a. What is the probability that the lock code will begin with 5?

Lets fix the first number as 5. Then there are 9 possibilities for the second digit, 8 for the third on and 7 for the last digit.

Thus, there are 1*9*8*7=504 codes which start with 5.

so 

P(first digit is five)=

b. What is the probability that the lock code will not contain the number 0? 

from the set {0, 1, 2...., } we exclude 0, and we are left with {1, 2, ...9}

from which we can form in total 9*8*7*6 codes which do not contain 0.

P(codes without 0)=n(codes without 0)/n(all codes)=(9*8*7*6)/(10*9*8*7)=6/10=0.6

Answer:

0.1 ; 0.6

8 0
3 years ago
Read 2 more answers
Solve the question below, please.
Ne4ueva [31]

Answer:

Adam: 52.26°

Step-by-step explanation:

Use Cosine Rule, Cos(C) = \frac{a^2 + b^2 - c^2}{2ab}, to find the angle of both players.

✔️Angle of Carlos:

Let the angle be C,

a = 50 ft

b = 40 ft

c = 24 ft

Plug in the values into the equation

Cos(C) = \frac{50^2 + 40^2 - 24^2}{2*50*40}

Cos(C) = \frac{3,524}{4,000}

C = Cos^{-1}(\frac{3,524}{4,000})

C = 28.24° (nearest hundredth)

✔️Angle of Adam:

Let the angle be C,

a = 30 ft

b = 22 ft

c = 24 ft

Plug in the values into the equation

Cos(C) = \frac{30^2 + 22^2 - 24^2}{2*30*22}

Cos(C) = \frac{808}{1,320}

C = Cos^{-1}(\frac{808}{1,320)}

C = 52.26° (nearest hundredth)

6 0
3 years ago
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