Answer:
Option A. 10 years
Step-by-step explanation:
we know that
Half-life 
is the amount of time required for a quantity to fall to half its value as measured at the beginning of the time period.
In this problem of a radioactive isotope is 10 years, which means that after 10 years half of the sample would have decayed and half would be left as it is.
After 10 years ( first half life) 5/2 = 2.5 g decays and 2.5 g remains left
Answer:
28
Step-by-step explanation:
28 times 2 = 56
28 times 1 = 28
56 + 28 = 84
- Turning on time be x
- Turning of time be y
If 19:00<=x<=19:30 and 4:00<=y<=6:00
Total time difference
- In order to mange time between 9--10 hours 30 minutes should be deducted in pairs from starting and ending .By which net deduction i e x-y=0
- Total starting options=x=15
- Total ending options=x=15
- Sample space=|S|=15+15=30
- E=1
Probability=
Answer:
y
Step-by-step explanation:
