Answer:
a. 1.0 eV
Explanation:
Given that
Voltage difference ,ΔV = 1 V
From work power energy
Work =Change in the kinetic energy
We know that work on the charge W= q ΔV
For electron ,e= 1.6 x 10⁻¹⁹ C
q=e= 1 x 1.6 x 10⁻¹⁹ C
Change in the kinetic energy
ΔKE= q ΔV
Now by putting the values
ΔKE= 1 x 1.6 x 10⁻¹⁹ x 1 C.V
We can also say that
ΔKE= 1 e.V
Therefore the answer will be a.
a). 1.0 eV
Answer:
Plato, Aristotle developed it further and used for 1400 years till Copernicus.
Explanation:
Answer:
<u><em>Energy:</em></u> <em>It is the capacity of work done by the body, </em>
- <em>for example, kinetic energy, potential energy, thermal energy, and so on. The S.I. unit of energy is Joule.</em>
<u>Mechanical Energy: </u><em>Mechanical energy is the energy of the body corresponding to its motion or change in its position. </em>
- <em>For example, potential energy and kinetic energy.</em>
<em />
<u><em>Law of conservation of energy: </em></u><em>According to the law of conservation of energy, the net energy of the system remains conserved.</em>
<em />
- <em>For example, in the case of elastic collision, the net energy of the system is conserved before and after the collision.</em>
<u><em></em></u>
<u><em>Law of conservation of energy for moving object: </em></u><em>The net energy of the moving object remains conserved.</em>
<em />
- <em>For example, the net energy of the ball sliding down the hill without any loss of energy remain conserved.</em>
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<em></em>
Answer:
Explanation:
In Coulomb's law the force between the charged objects depends on the distance between them which is inversely proportional to the force and the charge of the objects which is directly proportional to the force with proportional constant K.
Because q₂ is near to another charged object q₁, then, it will experience an electric force exerted by q₁.
F₁₂ = K |q₁| |q₂|/r²
= K (|-e|) (|+e|)/r²
= (9.0 x 10⁹ N.m²/C²) x (1.6 x 10⁻¹⁹ C) x (1.6 x 10⁻¹⁹ C)/ (0.80 x 10⁻⁹)²
= 3.6 x 10⁻¹⁰ N
Force F₁₂ = F₂₁
Because the two charged objects have different signs , then, the force between them will be an attractive force.
Answer:
To determine the specific heat capacity of another liquid, you could pour a measured mass of the hot liquid into the calorimeter (whose heat capacity is now known), and measure the fall in temperature of the liquid and the rise in temperature of the calorimeter, and hence deduce the specific heat capacity of the liquid
Explanation: