Question

B. the hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, how far does he travel while stopping? (2 points)

Answer 1

The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.

The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.

These equations link five kinematic variables:

Displacement (denoted by Δx)

Initial Velocity v0

Final Velocity denoted by v

Time interval (denoted by t)

Constant acceleration (denoted by a)

These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.

v = u + at

0 = 9.5 + a (2)

a = - 9.5 /2  m/$s^{2}$

$v^{2}$ = $u^{2}$ + 2as

0 =  $(9.5)^{2}$ + 2* (- 9.5 /2) * s

-  $(9.5)^{2}$  = - 9.5 s

s = 9.5 m

To learn more about kinematics here

brainly.com/question/27126557

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