Answer:
a) 0.303 s b) 6.77 m/s c) - 2.97 m/s d) 7.39 m/s
Explanation:
horizontal distance travel = 2.050 m, vertical distance travel = 0.45 m
Using equation of linear motion
Sy = Uy t + 1/2 gt² Uy is the inital vertical component of the velocity, t is the time taken for the vertical motion in seconds, and S is the vertical distance traveled, taken downward vertical motion as negative
-0.45 = 0 - 0.5 × 9.81×t²
0.45 / (0.5 × 9.81) = t²
t = √0.0917 = 0.303 s
b) horizontal distance traveled = horizontal velocity (Ux) × t
Ux = horizontal distance traveled / t = 2.050 / 0.303 = 6.77 m/s
c) Velocity in the vertical direction can be calculated using
Vy = Uy - gt where g is negative since initial U is zero
Vy = - 9.81 × 0.303 = - 2.97 m/s
d) the magnitude of the velocity = resultant of the the two velocity
using Pythagoras theorem
the magnitude of the velocity = √ ( 6.77² + 2.97²) = 7.39 m/s
at angle = tan^-1 ( 2.97 / 6.77) = 23.69⁰
