Answer:
B = 0.8 T
Explanation:
It is given that,
Radius of circular loop, r = 0.75 m
Current in the loop, I = 3 A
The loop may be rotated about an axis that passes through the center and lies in the plane of the loop.
When the orientation of the normal to the loop with respect to the direction of the magnetic field is 25°, the torque on the coil is 1.8 Nm.
We need to find the magnitude of the uniform magnetic field exerting this torque on the loop. Torque acting on the loop is given by :
B is magnetic field
So, the magnitude of the uniform magnetic field exerting this torque on the loop is 0.8 T.
It takes more work to use a meat grinder
This question involves the concepts of th magnetic field and current.
The magnetic field created by the current at the house is "6.75 x 10⁻⁷ T".
<h3>Magnetic Field</h3>
The magnetic field created by a current carrying wire can be given by the following formula:
where,
- B = magnetic field = ?
= permeabiliy of free space =4π x 10⁻⁷- I = current = 152 A
- r = distance = 45 m
B = 6.75 x 10⁻⁷ T
Learn more about magnetic field here:
brainly.com/question/23096032
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Very specific alignment of the Sun, Earth, and Moon. If the Moon is lined up precisely with the Sun from the Earth's point of view, the Moon will block Sunlight from reaching the Earth, causing a solar eclipse.
It IS <span>PE = (1200 kg)(9.8 m/s²)(42 m) = 493,920 J </span>
