False, it must be either empty or filled with electrons order to be most stable.
Answer:
d) A - 70% B - 30%
Explanation:
If x is the abundance of A, and 1−x is the abundance of B, then:
x (32.0) + (1−x) (33.0) = 32.3
32x + 33 − 33x = 32.3
33 − x = 32.3
x = 0.7
The abundance of A is 70%, and the abundance of B is 30%.
Answer:
b. Two moles of thiosulfate anion needed to react with one mole of hypochlorite anion.
Explanation:
1. Hypochlorite with iodide
2I⁻ ⟶ I₂ + 2e⁻
<u>ClO⁻ + 2H⁺ + 2e⁻ ⟶ Cl⁻ + H₂O </u>
2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂ + Cl⁻ + H₂O
2. Thiosulfate with iodine
2S₂O₃²⁻ ⟶ S₄O₆²⁻ + 2e⁻
<u> I₂ + 2e⁻ ⟶ 2I⁻ </u>
2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻
3. Sum of the reactions
2I⁻ + ClO⁻ + 2H⁺ ⟶ I₂ + Cl⁻ + H₂O
<u> 2S₂O₃²⁻ + I₂ ⟶ S₄O₆²⁻ + 2I⁻ </u>
2I⁻ + ClO⁻ + 2S₂O₃²⁻ + 2H⁺ ⟶ I₂ + Cl⁻ + S₄O₆²⁻ + H₂O
4. Molar ratio
S₂O₃²⁻:ClO⁻ = 2:1
Answer:
False
Explanation:
Metamorphic rocks form when rocks are subjected to high heat, high pressure, hot mineral-rich fluids or, more commonly, some combination of these factors.
This question is reffering to sedimentary rocks, so it's false.
First i wanted to say you look preety LOL
1) Determine the rate constant for the reaction:
<span>k = (ln 2) / t_1/2 <--- I'll leave you to figure out how that came to be. Hint: use the integrate form of the first-order rate law </span>
<span>k = (ln 2) / 23.6 min </span>
<span>k = 0.02937 min^-1 <--- keep a few extra digits </span>
<span>1) use the integrated form of the first-order rate law: </span>
<span>ln A = -kt + ln A_o </span>
<span>ln A = - (0.02937 min^-1) (120 min) + ln 2.50 </span>
<span>ln A = -3.5244 + 0.91629 </span>
<span>ln A = -2.60811 </span>
<span>A = 0.07367 M <--- round off more as you see fit </span>
<span>Here's another way: </span>
<span>120 min / 23.6 min = 5.106383 half-lives </span>
<span>(0.5)^5.106383 = 0.02902856 <--- the decimal amount remaining after 5.106383 half-lives </span>
<span>0.02902856 x 2.50 M = the answer</span>
