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2 years ago

2.15 mol of hydrogen sulfide, H2S

1 answer:

8 0

Equation below, how many moles of hydrogen sulfide (H2S) are produced? HCl + Na2S → H2S + 2 NaCl. A) 1 mol. B) 1.25 mol. (C) 2.5 mol.

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Which substance is a compound iron or nitrogen oxide

Zanzabum

I think it might be Nitrogen dioxide, but please check behind

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2 years ago

Read 2 more answers

Give two reasons why scientists create models to study atoms.

mariarad [96]

IT will be easy to know how chemical reactions occur
It will helps to know the fundamental particles of an atom

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3 years ago

If 3.1 moles of potassium chloride react with oxygen, how many moles of potassium chlorate would be produced?

Likurg_2 [28]

Answer: 19 dollar fortnite card Explanation:who wants it

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2 years ago

Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy

barxatty [35]

Answer:

1. $S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

2. $Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

3.The electron affinity of $Mg^{2+}$ is zero.

4. $O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

Explanation:

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of $S^{-}$ is as follows.

$S^{-}(g)+e^{-} \rightarrow S^{2-}(g)$

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

$Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}$

The electronic configuration of Mg: $1s^{2}2s^{2}2p^{6}3s^{2}$

By the removal of two electrons from a magnesium element we get $Mg^{2+}$ ion.

$Mg^{2+}$ has inert gas configuration i.e, $1s^{2}2s^{2}2p^{6}$

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of $Mg^{2+}$ is zero.

The ionization energy of $O^{2-}$ is follows.

$O^{2-}(g) \rightarrow O^{-}(g)+e^{-}$

3 0

2 years ago

5. A plane starting from rest is accelerated to its takeoff velocity of 75 m/s during a 5

LuckyWell [14K]

Answer:

answer is 14

Explanation:

A= v-u/t

A = 75 - 0/5

A = 14

v = final velocity

U = initial velocity

T = time taken

8 0

2 years ago