<em><u>the</u></em><em><u> </u></em><em><u>number</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>neutrons</u></em><em><u> </u></em><em><u>i</u></em><em><u>n</u></em><em><u> </u></em><em><u>aluminium</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>1</u></em><em><u>4</u></em>
Answer:
Option D. AlCl₃, MgC₂
Explanation:
We need to dissociate all the salts, to determine the i. (Van't Hoff factor).
The salt who has the highest value, will be the better conductor of electricity
CsCl → Cs⁺ + Cl⁻ i = 2
CaCl → Ca²⁺ + Cl⁻ i = 2
CaS → Ca²⁺ + S⁻² i = 2
Li₂S → 2Li⁺ + S⁻² i = 3
KBr → K⁺ + Br⁻ i = 2
AlCl₃ → Al³⁺ + 3Cl⁻ i = 4
MgC₂ → Mg²⁺ + 2C⁻ i = 3
KI → K⁺ + I⁻ i = 2
K₂S → 2K⁺ + S⁻² i = 3
The biggest i, is in pair D.
Answer:
[See Below]
Explanation:
I'd say 44 something. It's probably ml but I can't see what it says on the tube.
Answer:
63.6%
Explanation:
The given compound is:
N₂O;
The problem here is to find the percent composition of nitrogen in the compound.
First find the molar mass of the compound:
Molar mass of N₂O = 2(14) + 16 = 44g/mol
So;
Percentage composition of Nitrogen =
x 100 = 63.6%