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kirill115 [55]
3 years ago
11

Juan Carlos placed 35 grams of ke into a dry, 200-gram container. The top of the container was attached tightly. When the ice wa

s completely melted, the student
A.35
B.165
C.200
D.235

20 POINTS!!
Chemistry
1 answer:
lianna [129]3 years ago
8 0
Correct answer is D
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The __________________ of a solution tells how many moles of solute are present per liter.
Stels [109]

Answer:

The MOLARITY of a solution tells how many moles of solute are present per liter

Explanation:

Molarity is a sort of concentration.

It is written as M (mol/L)

5 0
3 years ago
Read 2 more answers
The rate law of a reaction is rate = k[D][X]. The units of the rate constant are ________.
bogdanovich [222]

Answer:

D

Explanation:

Hello!

Since the rate must have the following units: mol/(L*s), the suitable units for k, considering that the term [D] [X] leads to mol^2/(L^2) (it means a second order kinetic law), are L/(mol*s), nevertheless, that answer isn't in the given options.

8 0
3 years ago
Write and balance the chemical equation for the reaction associated with ΔHof of Li3N(s). What is the sum of all of the coeffici
ivann1987 [24]

Explanation:

In this reaction, the reactants are Li and N2. The product is Li3N

So we have;

Li + N2 → Li3N

Upon balancing, we have;

6Li + N2 → 2 Li3N

The sum of the coefficients is 6 + 1 + 2 = 9

5 0
3 years ago
The diameter of metal wire is often referred to by its American wire-gauge number. A 16 gauge-wire has a diameter of 0.05082 in.
lubasha [3.4K]

Answer:

length of wire = 38.82 m

Explanation:

∴ 16 gauge ≡ 0.05082 in * ( 2.54 cm/in ) = 0.12908 cm

∴ m spool = 1 Lb = 453.592 g

∴ ρ = 8.92 g/cm³

cross section area:

⇒ A = π*D²/4 = π*(0.12908)²/4 = 0.0131 cm²

⇒ L = ((453.592 g) *(cm³/8.92 g)) / ( 0.0131 cm² )

⇒ L = 3881.765 cm * ( m/100cm) = 38.82 m

8 0
3 years ago
What is the final pressure (expressed in atm) of a 3.05 L system initially at 724 mm Hg and 298 K, that is compressed to a final
maksim [4K]

Hey there!:

V1 = 3.05 L

V2 = 3.00 L

P1 = 724 mmHg

P2 = to be calculated

T1 = 298 K

T2 = 273 K

Therefore:

P1*V1  / T1  = P2*V2 / T2

P2 = ( P1*V1 / T1  )   * T2 / V2

P2 = 724 * 3.05 * 273 / 298 * 3.00

P2 = 602838.6 / 894

P2 = 674.31 mmHg

1 atm ----------- 760 mmHg

atm ------------- 674.31 mHg

= 674.31 * 1 / 760

= 0.887 atm

Hope this helps!

5 0
3 years ago
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