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Levart [38]
3 years ago
12

For the following system, if you isolated x in the second equation to use the subsition method, what expression would you subsit

ute into the first equation?
2x + y = 8
-x - 3y = -12

A. 3y + 12
B. -3y + 12
C. 3y - 12
D. -3y - 12​
Mathematics
1 answer:
kkurt [141]3 years ago
7 0
A.3y+12

i think so,or maybe D or B
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Solve this quadratic equation using the quadratic formula.<br> 2x^2 - 2x = 0
lakkis [162]

Answer:

27

Step-by-step explanation:

The answer is x=27

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Find the measure of two supplementary angles, ∠A and ∠B, if m∠A = (3x – 7)° and m∠B = (2x + 2)°. =180
nikklg [1K]

Answers:

Angle A = 104 degrees

Angle B = 76 degrees

=================================

Supplementary angles add to 180 degrees.

A+B = 180

(3x-7)+(2x+2) = 180

5x-5 = 180

5x-5+5 = 180+5 ... add 5 to both sides

5x = 185

5x/5 = 185/5 .... divide both sides by 5

x = 37

Use x =37 to find

Angle A = 3x-7 = 3*37-7 = 111-7 = 104 degrees

Angle B = 2x+2 = 2*37+2 = 74+2 = 76 degrees

As a check: A+B = 104+76 = 180 so that helps confirm the answer

4 0
3 years ago
I really need help please
Iteru [2.4K]
Answer is C
Because 2 is your Y intercept and -1/2 means your going to move down 1 then move 2 to the right
7 0
3 years ago
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The cash price of a television is $580.
Drupady [299]

Answer:

n=25% or 0.25

Step-by-step explanation:

865= 580(n%)+ 6(120)

865= 580 (n%) +720

865-720= 145

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divide both by 580, you get 0.25=n%

5 0
3 years ago
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
3 years ago
Read 2 more answers
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