Question

Find the value of expression - 17x-19xpwer4 - 21x power 2,when x=3​

Answer 1

Answer:

$-17x - 19x^4 - 21x^2 = -1779$ when $x = 3$

Step-by-step explanation:

Given

$-17x - 19x^4 - 21x^2$

$x = 3$

Required

Solve

Substitute 3 for x in $-17x - 19x^4 - 21x^2$

$-17x - 19x^4 - 21x^2 = -17*3 - 19*3^4 - 21*3^2$

Evaluate all exponents

$-17x - 19x^4 - 21x^2 = -17*3 - 19*81 - 21*9$

$-17x - 19x^4 - 21x^2 = -51 - 1539- 189$

$-17x - 19x^4 - 21x^2 = -1779$