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VikaD [51]
3 years ago
6

Which scenario matches the graph?

Mathematics
1 answer:
liubo4ka [24]3 years ago
8 0
Answer: The cost of hiring a house painter will cost $60 per day
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Can we do the sum of three odd number is equal to 30 ,,number using from 1 to 15 one number can repeat
kupik [55]
No you can not do get 30 with the sum of 3 odd numbers

5 0
3 years ago
There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
3 years ago
Graph the line with slope <br> −3/4<br><br> passing through the point <br> , (3,3)
Nookie1986 [14]
Y = mx + b
slope(m) = -3/4
(3,3)....x = 3 and y = 3
now we sub and find b, the y int
3 = -3/4(3) + b
3 = -9/4 + b
3 + 9/4 = b
12/4 + 9/4 = b
21/4 = b.....or 5.25 for graphing purposes

so ur equation is : y = -3/4x + 21/4

ur y int = (0,21/4) or (0,5.25)

ur x int can be found by subbing in 0 for y and solving for x
y = -3/4x + 21/4
0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
x = 84/12 = 7.....so ur x int is (7,0)

so plot ur points (7,0) and (0,5.25)....now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)




8 0
3 years ago
Absolute value equations <br> 10 6v + 3 = 30
konstantin123 [22]
Your answers would be 30
7 0
3 years ago
729 = __ to the 3rd power
TEA [102]
The answer is 9 because 9 to the second power is 81 and 81*9 = 729 :)))
i hope this is helpful 
have a nice day 
3 0
3 years ago
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