3x^3+0x^2-2x+k:x-2=3x^2+6x+10
3x^2-6x^2
6x^2-2x
6x^2-12x
10x+k
10x-20
k+20
Thus k=-20
Answer:
The measure of angle A is 
Step-by-step explanation:
we know that
Applying the law of cosines
substitute the values and solve for cos(A)
![cos(A)=[22^{2}+18^{2}-31^{2}]/(2(22)(18))\\ \\cos(A)=-0.193182\\ \\A=arccos(-0.193182)=101\°](https://tex.z-dn.net/?f=cos%28A%29%3D%5B22%5E%7B2%7D%2B18%5E%7B2%7D-31%5E%7B2%7D%5D%2F%282%2822%29%2818%29%29%5C%5C%20%5C%5Ccos%28A%29%3D-0.193182%5C%5C%20%5C%5CA%3Darccos%28-0.193182%29%3D101%5C%C2%B0)
Plug in the x value.
3(1-2)2=?
1-2= -1
3(-1)= -3
-3(2)= -6.
The answer is -6.
D=rt
So you're going to plug in the values listed: r= 9 1/2 and t=1 3/4
This will give you:
d=(9.5)(1.75)
Then you solve:
d=16.625
You should probably convert that decimal answer into a fraction since you're question gave it to you as a fraction.
You have to use the formule: y2-y1/x2-x1
-2-(-2)/4-(-3)=0/7
