Division Property of Equality.
Always use opposite operation with side that contains variable.
Isolate variable.
Divide 4 by 4 to get it by itself.
Now do the same to other side.
<span> half life i= 78 hours
amount after 78 hours is 395 kg:
395 = 790e^(k*78)
Dividing by 790 and taking natural log
ln (395/790) = (k*78)
-0.6931 = 78k
-0.00888 = k
lets calculate how much is left after 18 hours:
Amount(18)
= 790e^(-0.00888*18)
Amount = 673.301 kg
hope this helps</span>
(1/12)X = 6800
6800/ (1/12) = X
X = 81600 (hours)
6800 (6.8 * 10^3) divided by 1/12 (12^-1) equals 81600. It will take 81600 hours for the pool to completely empty at a rate of 0.833333333 or 12^-1 gallons per second.
Answer:
<h3>2T/9</h3>
Step-by-step explanation:
A construction manager needs 12 workers to complete a building project in 54 days, we can write;
12 workers = 54 days
T find the number of workers needed to complete the same project in T days, we will write;
x workers = T days
Divide both equations
12/x = 54/T
Cross multiply
12T = 54x
x = 12T/54
x = 2T/9
Hence the number of workers needed to complete the same project in T days is 2T/9 workers
Given 2.50x + 3.50y < 30.
Where x represent the number of hamburgers and y represent the number of cheeseburgers.
Now question is to find the maximum value of hamburgers Ben could have sold when he has sold 4 cheeseburgers.
So, first step is to plug in y=4 in the given inequality. So,
2.50x+3.50(4)<30
2.50x+14 <30
2.50x<30- 14 Subtracting 14 from each sides.
2.50x< 16
Dividing each sides by 2.50.
x<6.4
Now x being number of hamburgers must be an integer , so tha maximum value of x can be 6,
thus x = 6 hamburgers
So, the maximum value of hamburgers Ben could have sold is 6*2.5=$15
Hope this helps!!