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katrin [286]
3 years ago
9

A city sewer pipe has a diameter of 7 ft and a length of 100 ft. Find the volume of the pipe. Use 3.14 as

Mathematics
2 answers:
son4ous [18]3 years ago
7 0

Answer:

3846.5 ft³

Step-by-step explanation:

<em>A pipe has the shape of a cylinder.</em>

<u>Volume of cylinder = πr²h</u>

<em>radius (r) = 7/2 = 3.5</em>

<em>height (h) = 100</em>

<em>π = 3.14</em>

Volume of cylinder = πr²h

Volume = 3.14 x (3.5)² x 100

Volume = 3846.5 ft³

Therefore, the volume of the pipe is 3846.5 ft³.

!!

Advocard [28]3 years ago
7 0

Answer:V =3846.5\ ft^3

Step-by-step explanation:

As we do not know the internal radius of the pipe, then to calculate its volume we assume that the pipe is full of water.

This means that the volume of the pipe is the volume of a cylinder with radius r = \frac{7}{2}\ ft  and length  h = 100\ ft

The volume of a cylinder is calculated using the following formula:

V =\pi r^2h

Then the volume is:

V =(3.14)(3.5)^2(100)

V =3846.5\ ft^3

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Answer: 20 + x

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3 years ago
A rectangle has coordinates A(-4, 3), B(0, 0), C(6, 8), D(2, 11). What is the area of the rectangle?
asambeis [7]

Any polygon given by a list of 2D vertex coordinates has area given by the shoelace formula.

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5 0
3 years ago
A small island is 3 kilometers from the nearest point p on the straight shoreline of a large lake. if a woman on the island can
yKpoI14uk [10]
The distance walked will be (12-x) km
the distance rowed will be (9+x²) km
A] The function T(x) will be given by:
Time=distance/speed
thus we shall have:
T(x)=[√(9+x²)]/2.5+(12-x)/4

B] To get the distance x=c that minimizes the time travel, we differentiate the above.
T'(x)=(1/2.5)[1/(2.5√9+x²)*2x-1/4]
this should give us 0 for x=c, thus
c/[2.5*√(9+c²)]-1/4=0
⇒c/[2.5*√(9+c²)]=1/4
c/√(9+c²)=2.5/4
squaring both sides we get:
c²/(9+c²)=5/8
8c²=5(9+c²)
8c²=45+5c²
3c²=45
c²=15
c=3.87 km

c] The least travel time is
T(c)=[√(9+c²)]/2.5+(12-c)/4
this will give us:
T(c)=[√(9+3.87²)]/2.5+(12-3.87)/4
T(c)=3.9999209~4 hours

d] The second derivative will be:
T"(x)=1/[2.5√(9+x²)]-x²/[2.5(9+x²)^(3/2)]
but
x=c=3.87
T"(x)=0.01668 hours/ mile²
Given that T(c)=0, while T(x)<0 for x<c and T(x)>0 for x>c proves that T(x)  decreases for x<c and increases for x>c, so there is a minimum at x=c


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bonufazy [111]

Answer:

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Step-by-step explanation:

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4 0
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7 0
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