Dependent and Independent Events
1 answer:
Answer:
Step-by-step explanation:
Hello!
If you consider the 6-sided dice to be balanced, then each result has the same probability of occurrence: P(1)=P(2)=P(3)=P(4)=P(5)=P(6)=
And each time Tom rolls the dice is independent of the other times, this means that you can disregard all previous rolls and calculate the 10nth time as if it is the 1st one.
Be the event A: "Tom rolled the dice for the 10nth time and obtained a 6"
The probability of A occurring will be P(A)= 1/6
On the other hand, the complement of "A" will be : "Tom rolled the dice for the 10nth time and didn't obtain a 6"
This means he could obtain a 1 or a 2 or a 3 or a 4 or a 5
You can calculate the probability pf this event by adding the probability of obtaining each value P()= P(1)+P(2)+P(3)+P(4)+P(5)= 1/6*5= 5/6
Or by subtracting the probability of A to the total probability of the sample space:
P()= 1 - P(A)= 1 - 1/6= 5/6
I hope this helps!
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+
= 34
The equation of a circle in standard form is
+
=
where (a , b) are the coordinates of the centre and r is the radius
The centre is at the midpoint of the endpoints and the radius is the distance from the centre to either of the 2 endpoints
Using the midpoint formula
midpoint = [(x
+
,
(
+
where (,
=(3,8) and (
,
=(-7,2)
centre = ((3-7),
(8+2)) = (-2,5)
Calculate r using the distance formula
r = √(-
)²+(
-
)²)
= √((3+2)²+(8-5)²) = √(25+9) = √34 ⇒ r² =(√34)² = 34
equation of circle is : (x+2)²+(y-5)² = 34