Solve. –51/2 + 63/4 + (-41/4)

2-2=____ I did this just so you can get points.

Rudik [331]

2-2=0
Lol, thanks! I appreciate it.

3 0

3 years ago

Read 2 more answers

Helpppp will mark brainliest.

Tju [1.3M]

8 ^ (-2) = 1 / 64
4 ^ (-3) = 1 / 64

4 0

4 years ago

Which of the following would you add to each side of the equation x-9=12 to get the variable by itself?

Afina-wow [57]

The answer is 9!!!!!!

7 0

4 years ago

the volume of a pyramid whose base is aright triangle is 234 units. If the two legs of the right triangle measures 9 units and 1

Kobotan [32]

If the volume of this pyramid is 234 units, the height of the pyramid is equal to 13 units.

<h3>How to calculate the volume of a pyramid.</h3>

Mathematically, the volume of a pyramid is given by the formula:

$Volume = \frac{1}{3} \times base\;area \times height$

For the base area:

The area of a right triangle is given by:

$A=\frac{ab}{2} \\\\A=\frac{9 \times 12}{2} \\\\A=\frac{108}{2}$

A = 54 square units.

Given the following data:

Volume of a pyramid = 234 units.

Side lengths of right triangle = 9 and 12 units.

Now, we can calculate the height of the pyramid:

$234 = \frac{1}{3} \times 54 \times height\\\\234=18h\\\\h=\frac{234}{18}$

h = 13 units.

Read more on pyramid here: brainly.com/question/16315790

7 0

2 years ago

We are conducting a hypothesis test to determine if fewer than 80% of ST 311 Hybrid students complete all modules before class.

Juli2301 [7.4K]

Answer:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

Step-by-step explanation:

1) Data given and notation

n=110 represent the random sample taken

X=97 represent the students who completed the modules before class

$\hat p=\frac{97}{110}=0.882$ estimated proportion of students who completed the modules before class

$p_o=0.8$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v{/tex} represent the p value (variable of interest) 2) Concepts and formulas to use We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.8 or 80%: Null hypothesis:[tex]p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.881 -0.8}{\sqrt{\frac{0.8(1-0.8)}{110}}}=2.124$

4) Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level assumed $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(Z$

So the p value obtained was a very high value and using the significance level assumed $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis.

Be Careful with the system of hypothesis!

If we conduct the test with the following hypothesis:

Null hypothesis: $p\leq 0.8$

Alternative hypothesis: $p > 0.8$

$p_v =P(Z>2.124)=0.013$

So the p value obtained was a very low value and using the significance level assumed $\alpha=0.05$ we have $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

5 0

4 years ago