Answer:
The number of moles = 0.66 mole
Explanation:
Given as :
The volume of container (V) = 10.0 liter
The temperature (T)= 373 kelvin
The pressure of gas (P) = 203 k pa = 2.0034 atm
Let the number of mole = n
Now from at ideal gas law
PV = nRT
Where R = 0.08206 L atm per mol per kelvin
SO, (2.0034 × 10 ) = n × 0.08206 × 373
Or, (20.034 ) = n × 30.608
∴ n =
Or n = 0.654
Hence the number of mole = 0.66 mole Answer
Answer:
2.48 g
Explanation:
From the question given above, the following data were obtained:
Original amount (N₀) = 10 g
Time (t) = 1407.6 million years
Amount remaining (N) =?
Next, we shall determine the rate of decay (K) of uranium-235. This can be obtained as follow:
NOTE: Uranium-235 has a half life of 700 million years.
Decay constant (K) =?
Half life (t½) = 700 million years
K = 0.693/t½
K = 0.693/700
K = 9.9×10¯⁴ / year
Therefore, Uranium-235 decay at a rate of 9.9×10¯⁴ / year.
Finally, we shall determine the amount of Uranium-235 remaining after 1407.6 million years as follow:
Original amount (N₀) = 10 g
Time (t) = 1407.6 million years
Decay constant (K) = 9.9×10¯⁴ / year
Amount remaining (N) =?
Log (N₀/N) = kt /2.3
Log (10/N) = (9.9×10¯⁴ × 1407.6) /2.3
Log (10/N) = 0.60588
10/N = antilog (0.60588)
10/N = 4.04
Cross multiply
10 = 4.04 × N
Divide both side by 4.04
N = 10/4.04
N = 2.48 g
Therefore, 2.48 g of uranium-235 is remaining after 1407.6 million years.
Red phosphorus and white phosphorus are solid is a physical property
Answer:
other the effect of temperature on plants
Answer:
-8024.832 J
Explanation:
The amount of heat energy lost or released, Q, can be calculated thus;
Q = m × c × ∆T
Where;
Q = amount of heat lost (J)
m = mass of substance (g)
c = specific heat capacity (J/g°C)
∆T = change in temperature (°C)
According to this question,
Q = ?
m = 24.3 g
c of Gold = 0.129 J/g°C
∆T = 20°C - 2580.0°C = -2560°C
Using Q = m × c × ∆T
Q = 24.3 × 0.129 × -2560°C
Q = -8024.832 J
This means that 8024.832 J of energy is lost or released.