Answer:
A) Concentration
Explanation:
When you add a chemical to itself it becomes more concentrated making it more powerful and faster
The Bohr Model, which was proposed by Niels Bohr in 1913
Answer:
The heat of combustion is -25 kJ/g = -2700 kJ/mol.
Explanation:
According to the Law of conservation of energy, the sum of the heat released by the combustion reaction and the heat absorbed by the bomb calorimeter is equal to zero.
Qcomb + Qcal = 0
Qcomb = - Qcal
The heat absorbed by the calorimeter can be calculated with the following expression.
Qcal = C × ΔT
where,
C is the heat capacity of the calorimeter
ΔT is the change in temperature
Then,
Qcomb = - Qcal
Qcomb = - C × ΔT
Qcomb = - 1.56 kJ/°C × 3.2°C = -5.0 kJ
Since this is the heat released when 0.1964 g o quinone burns, the energy of combustion per gram is:

The molar mass of quinone (C₆H₄O₂) is 108 g/mol. Then, the energy of combustion per mole is:

Answer:It would never stop until something hit the ball, to slow it down.
Explanation:
This is so because there is no gravitational pull in space.
Answer:
12.01
Explanation:
(12.00*98.93% + 13*1.07%) /100% = 12.01