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Two Half Cell reactions are as,
Reduction: PbO₂ + 2e⁻ → Pb²⁺
As it is acidic medium reaction, so add H⁺ on reactant side as it has more number of oxygen atoms and add H₂O on product side, and balance tehe elements, So,
4 H⁺ + PbO₂ + 2e⁻ → Pb²⁺ + 2 H₂O (1)
Oxidation: I⁻ → I₂ + 1e⁻
Balance Number of elements along with electrons,
2 I⁻ → I₂ + 2e⁻ (2)
Compare eq. 1 and 2,
4 H⁺ + PbO₂ + 2e⁻ → Pb²⁺ + 2 H₂O
2 I⁻ → I₂ + 2e⁻
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
PbO₂ + 2 I⁻ + 4 H⁺ → Pb²⁺ + I₂ + 2H₂O
Number of Coefficients = 11
Answer:
c. the soluble compound exists as dissolved ions in a solution while insoluble compound forms as a precipitated.
Explanation:
Let's consider an example of a double displacement reaction that produces a soluble compound and an insoluble one.
BaCl₂(aq) + Na₂SO₄(aq) ⇒ NaCl(aq) + BaSO₄(s)↓
NaCl is a soluble compound so it is dissolved in the solution. It is also an electrolyte so it ionizes in water according to the following equation:
NaCl(aq) ⇒ Na⁺(aq) + Cl⁻(aq)
BaSO₄ is insoluble so it remains as a precipitate.
It is 2.5g/ml. You can find this answer by taking the mass (25g) and dividing it by the volume (10ml) and you will get your answer of 2.5g/ml.