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OLEGan [10]
3 years ago
8

What is the mass in grams of 0.280 mole sample of sodium hydroxide NaOH​

Chemistry
1 answer:
vivado [14]3 years ago
4 0

Answer:

The mass of 0.280 mole sample of sodium hydroxide NaOH​ is 11.2 grams.

Explanation:

To know the mass in grams of 0.280 moles of sample of sodium hydroxide NaOH, you must know the molar mass of the compound, that is, the mass of one mole of a substance, which can be an element or a compound.

So you know:

  • Na: 23 g/mole
  • O: 16 g/mole
  • H: 1 g/mole

So, the molar mass of NaOH is:

NaOH= 23 g/mole + 16 g/mole+ 1 g/mole= 40 g/mole

Then the following rule of three can be applied: if in 1 mole of sodium hydroxide there are 40 grams, in 0.280 moles how much mass is there?

mass=\frac{0.28 moles*40 grams}{1 mole}

mass= 11.2 grams

<u><em>The mass of 0.280 mole sample of sodium hydroxide NaOH​ is 11.2 grams.</em></u>

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aqueous lithium hydroxide solution is used to purify air (remove co2) in spacecrafts and submarines. the pressure of carbon diox
oksano4ka [1.4K]

The mass of the water is 1580 g.

<h3>What is the amount of water formed?</h3>

We know that the ideal gas equation can be used to obtain the number of moles of the gas. We have been told that the pressure of the gas reduced from  7.9 x 10-3 atm to  1.2 x 10-4 atm. The change in pressure can be used obtain the number of moles.

Change in pressure = 7.9 x 10-3 - 1.2 x 10-4 = 7.78 * 10^-3 atm

Using;

PV = nRT

n = PV/RT

n = 7.78 * 10^-3 atm *  2.4 x10^5 l/0.082 * (39 + 273)

n = 85 moles

Since 1 mole of carbon dioxide produces 1 mole of water

85 moles of carbon dioxide produces 85 mole of water

Mass of water produced = 85 mole  * 18 g/mol

= 1580 g

Learn more about ideal gas equation:brainly.com/question/4147359

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6 0
1 year ago
An unknown amount of sodium azide (NaN3) reacts and produces 0.033 moles of nitrogen gas. What mass of sodium metal is produced
Monica [59]

Answer:

Mass of sodium metal is 130.87 gram

Explanation:

The complete reaction is

2 NaN3 --> 2 Na + 3 N2

We know that PV = nRT

n = \frac{PV}{RT}

On substituting the given values, we get

n = \frac{\frac{99707}{101325}*75 }{0.082 *(273.15 +15)} \\n = 3.02moles of N2

Sodium azide's molar mass

3.02 *(2/3) = 2.013 moles

Mass = 2.03 * 65.01 = 130.87 gram

3 0
3 years ago
calculate the mass of 120cc nitrogen present at STP. how many number of molecules are present in it?​
Stells [14]

Answer:

0.15008\ \text{g}

3.23\times 10^{21}

Explanation:

1 mol of nitrogen at STP = 22.4 L = 22400 cc

n = Mol of N_2 = \dfrac{120}{22400}=0.00536\ \text{mol}

M = Molar mass of N_2 = 28\ \text{g/mol}

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

Mass of N_2 is

m=nM\\\Rightarrow m=0.00536\times 28\\\Rightarrow m=0.15008\ \text{g}

Mass of the nitrogen is 0.15008\ \text{g}

Number of molecules is given by

nN_A=0.00536\times 6.022\times 10^{23}=3.23\times 10^{21}\ \text{molecules}

The number of molecules present in it are 3.23\times 10^{21}

5 0
3 years ago
Elaborate on the nuclear model of the atom.
GarryVolchara [31]

Answer:

D

Explanation:

The nuclear model of the atom was proposed by Ernest Rutherford.

In his submission, the atom consists of a dense positive nucleus with electrons moving round this nucleus as planets move round the sun. He likened his model to the solar system. The nucleus is at the center of this system just as the sun is at the center of the solar system.

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3 years ago
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