In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure. They are created by moving electrons in double or triple bonds, and not atoms.
Phenol, 
and methanol, 
both are alcohols that contain an 
group attached to carbon atom.
Due to loss of 1 
from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1 it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.
The structures of the anions resulting from loss of 1 from phenol and methanol is shown in the image.
Answer:
The answer is
<h2>0.307 g/cm³</h2>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of box is 345 g
volume = 1125 cm³
The density of the object is
We have the final answer as
<h3>0.307 g/cm³</h3>
Hope this helps you
Answer:
Explanation:
Hello,
In this case, considering that the density of a body is computed given its mass and volume:
Taking into account that the mass is 24.32 g and the volume is computed via the difference between the volume of the water with the brass and the volume of water by itself as follows:
The density of the piece of brass turns out:
Best regards.
Answer:
The heat of vaporisation of methanol is "3.48 KJ/Mol"
Explanation:
The amount of heat energy required to convert or transform 1 gram of liquid to vapour is called heat of vaporisation
When 8.7 KJ of heat energy is required to vaporize 2.5 mol of liquid methanol.
Hence, for 1 mol of liquid methanol, amount of heat energy required to evaporate the methanol is = 
= 3.48 KJ
So, the heat of vaporization 
Therefore, the heat of vaporization of methanol is 3.48KJ/Mol
O valence electron number is the answer
