Answer:
V₂ = 16.5 L
Explanation:
To solve this problem we use <em>Avogadro's law, </em>which applies when temperature and pressure remain constant:
V₁/n₁ = V₂/n₂
In this case, V₁ is 22.0 L, n₁ is [mol CO + mol NO], V₂ is our unknown, and n₂ is [mol CO₂ + mol N₂].
- n₁ = mol CO + mol NO = 0.1900 + 0.1900 = 0.3800 mol
<em>We use the reaction to calculate n₂</em>:
2CO(g) + 2NO(g) → 2CO₂(g) + N₂(g)
0.1900 mol CO * 
0.1900 mol CO₂
0.1900 mol NO * 
0.095 mol N₂
- n₂ = mol CO₂ + mol N₂ = 0.1900 + 0.095 = 0.2850 mol
Calculating V₂:
22.0 L / 0.3800 mol = V₂ / 0.2850 mol
V₂ = 16.5 L
Answer:
The first thing that comes to my mind the moment I get up is when will I finish all my works and how will I pass 10th.
Answer:
Explanation:
Animal waste is broken down, producing methane gas
Answer:
V₂ = 4.0L
Explanation:
Decreasing temperature => Decreasing Volume (Charles Law)
For a given volume, use a temperature ratio that will give a smaller volume.
Volume at lower temp = 4.6L(70K/82K) = 4.0L ... Using (82K/70K) would give a larger volume => contrary to temperature effects on gas volumes when pressure and mass are kept constant.
Pressure effects on Gas Volumes:
Note: The same idea is applied to pressure effects on gas volumes also except that changes in pressure affect gas volumes indirectly. That is, an increase in pressure => decrease in volume, or a decrease in pressure => increase in volume. Boyles Law => V ∝ 1/P.
Given a gas volume of 4.60L at 760mmHg, what is volume at 848mmHg?
Increasing pressure => Decreases Volume (Boyles Law)
For the given volume use a pressure ratio that will give a smaller volume.
Volume at higher pressure = 4.6L(760mm/848mm) =4.1L. Using (848mm/760mm) would give a larger volume => contrary to pressure effects on gas volume when temperature and mass of gas are kept constant.
