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Vilka [71]
3 years ago
8

A 687.80-g sample of a noble is held in a 15 L cylinder tank at 3800 torr and a temperature of 22 degrees C. Identify the gas.

Chemistry
1 answer:
BARSIC [14]3 years ago
8 0

Answer:.......................

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7. If a waste container has 87.0 mL of 0.234 M acetic acid, how many milliliters of 2.00 M sodium
Naya [18.7K]

Answer:

V_{base}=10.2mL

Explanation:

Hello.

In this case, since the neutralization of the acid requires equal number of moles of both acid and base:

n_{acid}=n_{base}

Whereas we can express it in terms of concentrations and volumes:

M_{acid}V_{acid}=M_{base}V_{base}

Thus, we can compute the volume of sodium hydroxide (base) as follows:

V_{base}=\frac{M_{acid}V_{acid}}{M_{base}} \\\\V_{base}=\frac{87.0mL*0.234M}{2.00M}\\ \\V_{base}=10.2mL

Best regards.

8 0
3 years ago
Help me please!!!( ꈍᴗꈍ)​
Dahasolnce [82]

Answer:

<h3>Which of the following increases with the increase in the temperature in case of a liquid?</h3><h2><em>Va</em><em>pour</em><em> </em><em> </em><em>Pressure</em><em> </em></h2>

Explanation:

When a closed container contains liquid, higher the temperature, higher the evaporation the evaporation will be.

So Vapour Pressure should be the correct answer.

6 0
2 years ago
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At equal concentrations would a nonelectrolyte (e.g. glucose) or electrolyte (e.g. nacl) containing solution have a lower freezi
Anestetic [448]
Answer is: solution of electrolyte will have lower freezing point than solution of nonelectrolyte.
This is because salt solution has more particles in of sodium chloride (sodium and chlorine ions) than in same concentration of glucose. Electrolytes better separates into particles in water because of their ionic bond.<span>
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6 0
3 years ago
How many grams of iron metal do you expect to be produced when 275 grams of an 65.5 percent by mass iron (II) nitrate solution r
Jlenok [28]

Answer:

75.5

Explanation:

4 0
3 years ago
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Hey I need help with this element, compound, and mixtures worksheet
Alika [10]

We should describe a little bit the legend.

A - Element - we should have circles with same color and not bonded together (argon gas).

B - Compound - here we may have circles with same or different color bonded together (water or oxygen which is a diatomic molecule).

C - Mixture of elements - circles with different colors not not bonded together (mixture of noble gases).

D - Mixture of compounds - circles with same or different color bonded together but we should see two or more types of connectivity between circles (mixture of water and ethanol).

E - Mixture of elements and compounds - circles with same or different color bonded together mixed with circles with same color and not bonded together (a mixture between oxygen which is a diatomic molecule and noble gas like argon).

Now we may answer the question:

1) B

2) C

3) D

4) D

5) A

6) B

7) B

8) E

9) E

10) D

11) B

12) D

13) D

14) D

15) D

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