Answer two quetions.......

A teacher wants to figure out the amount of a solution that is needed for a titration experiment in a class lab. The class has 1

baherus [9]

15 students times 50 mL per student. 750 mL Then 750 times two so you can do two experiments per person.

3 0

3 years ago

Read 2 more answers

Is baking cake a acid base reaction

Zinaida [17]

When baking powder is added to a cake, the acid base reaction it undergoes with the acidic butter produces the carbon dioxide that makes the cake rise.

6 0

3 years ago

Isotopes of the same element have different

Nana76 [90]

Isotopes of the same element have different mass numbers.

C. mass numbers.

one mole of copper has 6.02 x 10²³ atoms

C. 6.02 * 10²³ atoms.

5 0

3 years ago

1.00 L of a gas at STP is compressed to 473mL. What is the new pressure of gas?

Ratling [72]

Hello!

1.00 L of a gas at STP is compressed to 473 mL. What is the new pressure of gas?

We have the following data:

Vo (initial volume) = 1.00 L

V (final volume) = 473 mL → 0.473 L

Po (initial pressure) = 1 atm (pressure exerted by the atmosphere - in STP)

P (final pressure) = ? (in atm)

We have an isothermal transformation, that is, its temperature remains constant, if the volume of the gas in the container decreases, so its pressure increases. Applying the data to the equation Boyle-Mariotte, we have:

$P_0*V_0 = P*V$

$1*1 = P*0.473$

$1 = 0.473\:P$

$0.473\:P = 1$

$P = \dfrac{1}{0.473}$

$\boxed{\boxed{P \approx 2.11\:atm}}\:\:\:\:\:\:\bf\green{\checkmark}$

Answer:

The new pressure of the gas is 2.11 atm

___________________________________

$\bf\blue{I\:Hope\:this\:helps,\:greetings ...\:Dexteright02!}\:\:\ddot{\smile}$

3 0

3 years ago

For the reaction of C 2H 4( g) with O 2( g), to form CO 2( g) and H 2O( g), what number of grams of CO 2 could be produced from

maksim [4K]

Answer:

4.58g of CO₂ could be produced

Explanation:

Based on the reaction:

C₂H₄(g) + 3O₂(g) → 2CO₂(g) + 2H₂O(g)

1 mole of C₂H₄ reacts with 3 moles of oxygen to produce 2 moles of CO₂

To solve this question we must find the moles of each reactant in order to find limiting reactant. With limiting reactant we can find the moles -And the mass- of CO₂ produced:

Moles C₂H₄ -Molar mass: 28.05g/mol-

2.0g * (1mol / 28.05g) = 0.0713moles

Moles O₂ -Molar mass: 32g/mol-

5.0g * (1mol / 32g) = 0.156moles

For a complete reaction of 0.0713 moles of C2H4 are required:

0.0713 moles C₂H₄ * (3 moles O₂ / 1 mol C₂H₄) = 0.214 moles of O₂

As there are just 0.156 moles, O₂ is limiting reactant.

The moles of CO₂ produced are:

0.156 moles O₂ * (2mol CO₂ / 3mol O₂) = 0.104 moles CO₂

The mass is -Molar mass CO₂: 44.01g/mol-

0.104 moles CO₂ * (44.01g / mol) =

<h3>4.58g of CO₂ could be produced</h3>

4 0

3 years ago