<span>Suppose you plant a seed and observe that a tree of large mass grows from it. The tree achieves a final mass that changes very little for years afterward.<span>
</span>Answer: Of the options presented above the one that is true about the tree is answer choice B) Both anabolic and catabolic reactions took place in the seed and tree when it was young and growing, and both continue now even though the tree reached a stable mass.
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Answer:
energy that is transmitted in the form of electromagnetic waves.
Explanation:
Radiant energy is the energy of electromagnetic waves. It is a form of energy that can travel through space. For example, we receive the heat from the sun, which is located very far from the earth via radiation. The sun's heat is not transmitted through any solid medium, but through a vacuum.
The cations and anions can be identified using cataloged reactions schemes. For instance, the copper II ion can be identified by reaction with sodium hydroxide.
The sodium cation is easily identified by flame test. sodium imparts a yellow color to a flame. The chloride ion is identified by the use of a mixture of HNO3/AgNO3 solution. The color of the precipitate shows which halide ion is present. A white precipitate indicates the presence of the chloride ion.
The potassium cation is also identified by flame test. The ion imparts a lilac color to flame. Addition of acidified FeSO4 solution is used to confirm the presence of the nitrate ion. Formation of a brown ring is a positive test for the nitrate ion.
For CuSO4, the presence of copper II ion can be confirmed using dilute NaOH. If a light blue precipitate is formed which dissolves in excess NaOH then the copper II ion is confirmed. The presence of the sulfate ion is confirmed using a solution of barium nitrate and dilute nitric acid. Formation of a white precipitate is a positive test for the sulfate ion.
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Answer:
V₂ = 107.84 L
Explanation:
Given data:
Initial volume = 100 L
Initial pressure = 80 KPa (80/101 =0.79 atm)
Initial temperature = 200 K
Final temperature =273 K
Final volume = ?
Final pressure = 1 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁T₂ /T₁P₂
V₂ = 0.79 atm × 100 L × 273 K / 200 K × 1 atm
V₂ =21567 atm.L.K /200 K.atm
V₂ = 107.84 L
