Answer:
The answer is "
"
Explanation:
When
is added in the chemical equation it reacts with sodium acetate so, it will give the following chemical equation:
In this, the
is a weak acid so, it not completely dissociated.
were strong electrolytes they are completely dissociated.
The
is a strong acid so, it is completely dissociated So, the net ionic equation is:
![CH_3COO^{-} \ (aq) + H^{+}\ (aq) \longrightarrow CH_3COOH \ (aq)](https://tex.z-dn.net/?f=CH_3COO%5E%7B-%7D%20%5C%20%28aq%29%20%2B%20H%5E%7B%2B%7D%5C%20%28aq%29%20%5Clongrightarrow%20CH_3COOH%20%5C%20%28aq%29)
Well, first we must remember that
![pK_{a}+pK_{b}=14](https://tex.z-dn.net/?f=pK_%7Ba%7D%2BpK_%7Bb%7D%3D14)
This is because
![K_{a}*K_{b}=10^{-14}](https://tex.z-dn.net/?f=K_%7Ba%7D%2AK_%7Bb%7D%3D10%5E%7B-14%7D)
![-log(K_{a}*K_{b})=-log(10^{-14})\\-logK_{a}+-logK_{b}=-log(10^{-14})\\pK_{a}+pK_{b}=14](https://tex.z-dn.net/?f=-log%28K_%7Ba%7D%2AK_%7Bb%7D%29%3D-log%2810%5E%7B-14%7D%29%5C%5C-logK_%7Ba%7D%2B-logK_%7Bb%7D%3D-log%2810%5E%7B-14%7D%29%5C%5CpK_%7Ba%7D%2BpK_%7Bb%7D%3D14)
So then
![pK_{b}=14-pK_{a}=14-3.2=1.8](https://tex.z-dn.net/?f=pK_%7Bb%7D%3D14-pK_%7Ba%7D%3D14-3.2%3D1.8)
Answer:
Examine the multiple bond for cis- and trans- isomers.
Explanation: