Answer:
Yes by AAA
Step-by-step explanation:
Angle A is the same for both triangles. Angle D is congruent to Angle A since BC and DE are parallel lines and same with angle E. So by AAA the triangles are similar
Area=wide times long
area=40
4=wide
40=4 times long
divide both sides by 4
10=long
10 yd long
First you have to multiply -2 and 2 which is -4x.
Then your going to distribute -4 to 4x which is -16x.
Now your going to distribute -4 and -3 which is 12.
So your simplified expression would be -16x + 12
Answer:
1st and 2nd statements are true.
Step-by-step explanation:
We are asked to choose the correct statements that can prove that quadrilateral DEFG is a parallelogram.
We will use parallelogram properties to answer this problem.
Since we know that a parallelogram has two sets of opposite angles congruent, therefore, 1st option is a correct choice.
Since a parallelogram has one set of opposite sides that are both congruent and parallel, therefore, second statement is true.
Since the consecutive angles of a parallelogram are supplementary, therefore, 3rd statement is not true.
Since the diagonals of parallelogram bisect each other, therefore, 4th statement is not true.
