Answer: False
=============================================
Explanation:
I'll use x in place of p.
The original equation 10x^2-5x = -8 becomes 10x^2-5x+8 = 0 after moving everything to one side.
Compare this to ax^2+bx+c = 0
We have
Plug those three values into the discriminant formula below
d = b^2 - 4ac
d = (-5)^2 - 4(10)(8)
d = 25 - 40*8
d = 25 - 320
d = -295
The discriminant is negative, which means we have no real solutions. If your teacher has covered complex or imaginary numbers, then you would say that the quadratic has 2 complex roots. If your teacher hasn't covered this topic yet, then you'd simply say "no real solutions".
Either way, this quadratic doesn't have exactly one solution. That only occurs when d = 0. Therefore, the original statement is false.
Answer:
yes
Step-by-step explanation:
First, put the equation of the line giveninto slope-intercept form by solving fory. You get y = 2x +5, so the slope is –2.Perpendicular lines have opposite-reciprocal slopes, so the slope of theline we want to find is 1/2. answer y=-1/2
Okay let's see.. 0.750
1.200
As we see 1 is bigger than 0.So that means 1/2 is bigger.Hope this helps! (;
The correct statement about the data collected by Ms. Pearson is that there is no association between a student's absences and the final average grades.
<h3>When do variables have a linear relationship?</h3>
The equation that represents a linear relationship is: a + bx
Where x represents the rate of increase. Thus, for linear equations, the functiion increases by a constant term.
Looking at the table, the average final grade does not increase by a constant term.
To learn more about linear functions, please check: brainly.com/question/26434260
