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Ilya [14]
3 years ago
9

The ratio of flowers the rose bushes bloom is 5 red for every 7 yellow. If there are 105 yellow rose blooms, about how many red

rose blooms are there?

Mathematics
1 answer:
sineoko [7]3 years ago
4 0

Answer:

147

Step-by-step explanation:

if you divide 105 by 5, you get 21. Multiply 7 by 21 to get your answer.

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mash [69]
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[4 - 3c + 1][6 - 3c + 1]
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[-3c + 5][-3c + 7]
-3c[-3c + 7] + 5[-3c + 7]
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7 0
3 years ago
Can someone help me
Ulleksa [173]

Answer:

10°

Step-by-step explanation:

180-20 = 160

<BCA = 160°

AC=CB because its Radius

so the angle for <CBA and <BAD also the same

(180 - 160) ÷ 2 = <BAD

<BAD = 10°

4 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP!! THANKS!!
Elena L [17]

Answer:

40

Step-by-step explanation:

The angles stay the same but, the position of the triangle changes.

Hope this helps,

kavitha

8 0
3 years ago
Read 2 more answers
Write an
Helga [31]

Answer:

Since the Line is Perpendicular

m.m'=-1

The line

y=x+8

Comparing with

Y=mx + C

m=1

m.m'=-1

m'=-1/m = -1/1 = -1.

y-y' = m'(x-x')

The point it passes is (-7,8)

y-8= -1(x--7)

y-8=-1(x+7)

y-8 = -x - 7

y + x -1 = 0.

or In Slope intercept Form

Just Make y the subject

y= -x + 1 ..... This is your answer.

Hope this helps!!!

6 0
2 years ago
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
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