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raketka [301]
3 years ago
9

FAST HELP!! Will mark brainliest!!

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

pls give brainliest

Step-by-step explanation:

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What's an equation that represents the number of teaspoons, t, contained in a cup, C?
strojnjashka [21]

Answer:

Step-by-step explanation:

t=C/ c

C=quantity in a cup

c=quantity in a teaspoon

5 0
3 years ago
The likelihood that a patient with a heart attack dies of the attack is 0.04 (i.e., 4 of 100 die of the attack). Suppose we have
Sonbull [250]

The probability solved by binomial distribution that all will survive is 0.8154.

<h3>What is Binomial distribution? </h3>

When each trial has the same probability of achieving a given value, the number of trials or observations is summarized using the binomial distribution. The likelihood of observing a specific number of successful outcomes in a specific number of trials is determined by the binomial distribution.

Computation of probability of all survived people from heart attack;

A heart attack patient has a 0.04 percent chance of dying from the attack (i.e., 4 of 100 die of the attack).

What is the likelihood that each of the five patients who experience a heart attack will survive?

We'll refer to a victory in this scenario as a heart attack (p = 0.04). In other words, we are interested in the likelihood that none of our n=5 patients will die (0 successes).

Each attack has a chance of being fatal or not, with a probability of 4 percent for all patients, and each patient's result is independent.

Assume for the purposes of this example that the five individuals being examined are unrelated, of the same age, and free of any concomitant disorders.

By binomial distribution,

\begin{gathered}P(0 \text { successes })=\frac{5 !}{0 !(5-0) !} 0.04^{0}(1-0.04)^{5-0} \\P(0 \text { successes })=\frac{5 !}{5 !}(1)(0.96)^{5}=(1)(1)(0.8154)=0.8154\end{gathered}

Therefore, with a 4 % chance that anyone will die, there is an 81.54% chance that every patient will survive the onslaught. The outcomes in this example could be 0, 1, 2, 3, 4 or 5 successes (fatalities).

To know more about Binomial Distribution, here

brainly.com/question/27794898

#SPJ4

6 0
2 years ago
suppose you are in your last semester of college and have a 2.75 GPA after 105 credit hours if you are taking 15 credit hours in
Valentin [98]

Answer:

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

Step-by-step explanation:

Given,

CGPA = 2.75

Credit hours = 105

Last semester GPA = 4

Last semester credit hours = 15

CGPA = \frac{sum of (Credit hours of each subject * GPA of each subject)}{Total credit hours}credit hours * gpa

in our case, it would be:

CGPA = \frac{(2.75*105)+(4*15}{105+15}

=> \frac{(288.75)+(60)}{120}

=> \frac{348.75}{120}

=> 2.90

The overall CGPA would be 2.90 so it is not possible for hum to secure a CGPA of 3 for graduation.

7 0
4 years ago
In what situation would you use an ANOVA statistical test over T-test?
expeople1 [14]

Step-by-step explanation:

when means of more than two groups are to be compared, ANOVA is perferred

5 0
2 years ago
What is the measure of the angle?
harkovskaia [24]

Answer:

20 degfress

Step-by-step explanation:

8 0
3 years ago
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