Answer:
a)How many different ways can you allocate the 22 students to the projects? =2300
b) how many different ways can you allocate the 22 students to the projects= 286
Step-by-step explanation:
check attachment for detail explanations
X+y = 12
x-y = 3
x = 3+y
Substitute it in 1st equation,
3+y+y=12
2y = 9
y = 4.5
Substitute it in 1st eq.,
x = 12-4.5 = 7.5
So, the two numbers are 7.5 & 4.5
Hope this helps!
2/3y-2/5=5
We move all terms to the left:
2/3y-2/5-(5)=0
Domain of the equation: 3y!=0
y!=0/3
y!=0
y∈R
determiningTheFunctionDomain
2/3y-5-2/5=0
We calculate fractions
There is no solution for this equation
Answer: y = (1 - 0.527)^t
Step-by-step explanation:
y=e^(-0.75t)
y=(e^-0.75)^t
y= 0.47236655^t
1 - 0.47236655 = 0.52763345
y = (1 - 0.527)^t
Answer:
Z = 34
Step-by-step explanation:
From the series, we have that:
a = -2
a + d = 7
Hence, -2 + d = 7
∴ d = 7 + 2 = 9
a + 2d = X; a + 3d = Y and a + 4d = Z
-2 + 4(9) = Z
∴ Z = 36 - 2 = 34
