Answer: 134.23g at 0° (horizontal) and 77.5g at 90° (vertical).
Explanation:
1) Since the mass of <span>155 g is suspended at 210 degrees, you need to find the components of its weight on the orthogonal coordinate system (0° and 90°).
</span>
<span>2) You do that using the trignometric ratios sine and cosine.
</span>
<span>Weight is mass × g.
</span>
<span>Weight of the object = 155g × g
</span>
<span>Angle, α = 210°
</span>
<span>Horizontal component (0°)
</span>
<span>cosα = horizontal / hypotenuse ⇒ horizontal = hypotenuse × cosα
</span>
⇒ horizontal = 155g × g × cos(210°) = - 134.23g × g
Vertical component
sinα = vertical / hypotenuse ⇒ vertical = hypotenuse × sinα
⇒ vertical = 155g × g × sin(210°) = -77.5g × g
3) Conclusion:
Therefore, the masses that must be suspended to balance the forces of the 155g mass are 134.23g at 0° (horizontal) and 77.5g at 90° (vertical).
Explanation:
Suppose the cheetah is initially positioned at x=0 (m) from the reference, and the gazelle is intially at poisiton x=d (m).
Then, at the worst case, that is when cheetah is running at the maximum case, the position of the gazelle relative to the reference must be larger than that of cheetah.
In equation form,



<u>Answer</u>
Chemical energy in to thermal energy
<u>Explanation</u>
When acetylene fuel is burning in presence of oxygen, we have chemical process taking place. The torch is used to heat metal to its kindling temperature in oxy-fuel cutting. The steam of gas is then trained on the metal burning it into a metal oxide that flows out of the spout.
So the energy transformation represents this process is <em>Chemical energy into thermal energy </em>
Answer:
68 ohm
Explanation:
Output Voltage, Vout = 5 V
Forward voltage, Vf = 3.65 V
Forward current, If = 20 mA = 0.02 A
Let the resistance is R.
Use the formula


R = 67.5 ohm
R = 68 ohm ( approx.)
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