Answer:
0.0003 m = 0.3 mm
Explanation:
For constructive interference in the Young's experiment.
The position of the mth fringe from the central fringe is given by
y = L(mλ/d)
λ = wavelength = 720 nm = 720 × 10⁻⁹ m
L = distance between slits and screen respectively = 1.0 m
d = separation of slits = 0.68 mm = 0.68 × 10⁻³ m
m = 2
y = 1(2 × 720 × 10⁻⁹/(0.68 × 10⁻³) = 0.00212 m = 2.12 mm
For the 620 nm light,
y = 1(2 × 620 × 10⁻⁹/(0.68 × 10⁻³) = 0.00182 m = 1.82 mm
Distance apart = 2.12 - 1.82 = 0.3 mm = 0.0003 m
Answer:
<em>Radius at liftoff 8.98 m</em>
Explanation:
At the working altitude;
maximum radius = 24 m
air pressure = 0.030 atm
air temperature = 200 K
At liftoff;
temperature = 349 K
pressure = 1 atm
radius = ?
<em>First, we assume balloon is spherical in nature,</em>
<em>and that the working gas obeys the gas laws.</em>
from the radius, we can find the volume of the balloon at working atmosphere.
Volume of a sphere = 
volume of balloon =
x 3.142 x
= 57913.34 m^3
using the gas equation,
= 
<em>The subscript 1 indicates the properties of the gas at working altitude, and the subscript 2 indicates properties of the gas at liftoff.</em>
imputing values, we have
= 
0.03 x 57913.34 x 349 = 200V2
V2 = 606352.67/200 = <em>3031.76 m^3 this is the volume occupied by the gas in the balloon at liftoff.</em>
from the formula volume of a sphere,
V =
=
x 3.142 x
= 3031.76
4.19
= 3031.76
= 3031.76/4.19
radius r of the balloon on liftoff =
= <em>8.98 m</em>
Explanation:
maturity also get disorganised
Answer:
Total kinetic energy of entire system is 3 mgl
Explanation:
Given two masses: m and 4m.
Since the pulley is frictionless and the thread is massless, the energy here is linked to the two masses.
Total kinetic energy of entire system = decrease in gravitational potential energy of the system.
Therefore, we have :
ΔKE = Δp
ΔKE = 4mgl - mgl
= 3 mgl
Total kinetic energy of entire system is 3 mgl
The answer is c and my reason is I have straight As