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djyliett [7]
3 years ago
8

What charge do the 2 objects have after charging by friction

Physics
1 answer:
Molodets [167]3 years ago
6 0

Explanation:

When two different materials are rubbed together, there is a transfer of electrons from one material to the other material. This causes one object to become positively charged (the electron loser) and the other object to become negatively charged (the electron gainer).

I hope it's helpful!!

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A slingshot is fired with an initial velocity of 100 m/s at an angle of 55° follows a parabolic trajectory and hits a stationary
erma4kov [3.2K]

Answer:

The horizontal speed with which the slingshot hits the balloon is approximately 57.358 m/s

Explanation:

The given parameters of the slingshot motion are;

The initial velocity of the slingshot, v = 100 m/s

The angle (to the horizontal) at which the slingshot is fired makes, θ = 55°

The path of the slingshot which hits the stationary balloon at the top of its flight = Parabolic trajectory

The horizontal component of the velocity = vₓ = v·cos(θ) = Constant

vₓ = 100 × cos(55°) ≈ 57.358

The horizontal speed with which the slingshot hits the balloon = vₓ ≈ 57.358 m/s.

4 0
3 years ago
What is astrometry? What is astrometry? measuring the positions of stars on the sky using metric units for distance (e.g. meters
Fofino [41]

Explanation:

It is a branch of astronomy wherein measurements of the positions and movements of celestial bodies are precisely are made.  

For the measurement, minute wobbling of the position of the body is detected. When the shift is detected periodically, the astronomers  come to know that the star is orbited by a planet.  

Also, basic data about the properties of the stars can be collected using this method.

5 0
3 years ago
If two metal balls each have a charge of -10^-6 C and the repulsive force between them is 1 N, how far apart are they? (Coulomb'
Vitek1552 [10]

Answer:

The distance between the charges is 9.5 cm

(c) is correct option

Explanation:

Given that,

Charge q= 10^{-6}\ C

Force F = 1 N

We need to calculate the distance between the charges

Using Coulomb's formula

F = \dfrac{kq_{1}q_{2}}{r^2}

Where, q = charge

r = distance

F = force

Put the value into the formula

1=\dfrac{9.0\times10^{9}\times(-10^{-6})^2}{r^2}

r=\sqrt{9\times10^{9}\times(-10^{-6})^2}

r=0.095\ m

r= 9.5\ cm

Hence, The distance between the charges is 9.5 cm

4 0
3 years ago
A thunderclap sends a sound wave through the air and the ocean below. The
marysya [2.9K]

Answer:

C. 14.93 m

Explanation:

The given frequency of the wave, f = 100 Hz

The given equation for the wave speed, <em>v</em>, is presented as follows;

v = f × λ

The speed of sound in water, v = 1,493 m/s

Therefore, we get;

The wavelength, λ = v/f

∴ λ = 1,493 m/s/(100 Hz) = 14.93 m

The wavelength, λ = 14.93 m.

8 0
3 years ago
Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits w
maks197457 [2]

Answer:

∅=2021rad

Explanation:

Coherent light with wavelength 540 nm passes through narrow slits with a separation of 0.370 mm . At a distance from the slits which is large compared to their separation, what is the phase difference (in radians) i the light from the two slits at an angle of 28.0 ∘ from the centerline?

A wave is a disturbance which travels through a medium, it transfers energy without a permanent displacement of the medium itself. this is an example of light wave

using the formula below

∅=\frac{2\pi*d }{\beta } sin\alpha

the phase difference is given from the above

d= distance/separation of slits .00037m

\beta=wavelength

540*10^-9m

\alpha=angle of two slits  28.0 ∘

∅=(\frac{2\pi*0.00037 }{540*10^-9} sin 28

∅=2021rad

there are large bright fringes from the centre line

3 0
3 years ago
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