Answer:
v_y = 14.55 m/s
Explanation:
given,
height at which gull is flying = 10.80 m
speed of the gull = 6 m/s
acceleration due to gravity = 9.8 m/s²
Relative to the seagull, the x-speed is 0,
because the seagull has the same x-speed.
Only the y-speed counts:
v_y = 14.55 m/s
hence, the speed at which the clam smash the rock is v_y = 14.55 m/s
I believe it’s tackling but I’m not quite sure
Answer:
a = 0.7267
, acceleration is positive therefore the speed is increasing
Explanation:
The definition of acceleration is
a = dv / dt
they give us the function of speed
v = - (t-1) sin (t² / 2)
a = - sin (t²/2) - (t-1) cos (t²/2) 2t / 2
a = - sin (t²/2) - t (t-1) cos (t²/2)
the acceleration for t = 4 s
a = - sin (4²/2) - 4 (4-1) cos (4²/2)
a = -sin 8 - 12 cos 8
remember that the angles are in radians
a = 0.7267
the problem does not indicate the units, but to be correct they must be m/s²
We see that the acceleration is positive therefore the speed is increasing
Answer:
This is to say that the vertical velocity changes by 9.8 m/s each second and the horizontal velocity never changes. This is indeed consistent with the fact that there is a vertical force acting upon a projectile but no horizontal force.
Explanation:
