The visible light has wavelength in therange 400 - 700 nano-meters. The wavelengths longer than visible light are: 1-Infrared waves (used in ringtone/mobile waves)2-microwaves -used to heat and cook food. 3- Radiowaves - used in communication
I can't find the attached circuit.
Maximum power transfer occurs when the load impedance
is equal to the internal impedance of the power source.
The van's AVERAGE speed on the way up the hill is
(1/2) (20 + 12) = (1/2) (32) = 16 m/s .
At an average speed of 16 m/s, it travels
(16 m/s) x (8 s) = 128 meters in 8 seconds.
We have a problem with three different state of the ratio of flow velocity to speed of sound.
That is,
a) Mach number to evaluate is 0.2, that mean we have a subsonic state.
The equation here for lift coefficient is,
![c_1 = 2\pi \alpha](https://tex.z-dn.net/?f=c_1%20%3D%202%5Cpi%20%5Calpha)
where
should be expressed in Rad.
![\alpha = \frac{5}{57.3}= 0.087](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B5%7D%7B57.3%7D%3D%200.087)
So replacing in equation for subsonic state,
![c_1 = 2\pi (0.087)=0.548](https://tex.z-dn.net/?f=c_1%20%3D%202%5Cpi%20%280.087%29%3D0.548)
b) In this situation we have a transonic state, so we need to use the Prandtl-Glauert rule,
![c_{t}=\frac{\c{t_0}}{\sqrt{1-M^2_{\infty}}} = \frac{0.548}{\sqrt{1-0.7^2}}=0.767](https://tex.z-dn.net/?f=c_%7Bt%7D%3D%5Cfrac%7B%5Cc%7Bt_0%7D%7D%7B%5Csqrt%7B1-M%5E2_%7B%5Cinfty%7D%7D%7D%20%3D%20%5Cfrac%7B0.548%7D%7B%5Csqrt%7B1-0.7%5E2%7D%7D%3D0.767)
c) For this case we have a supersonic state, so we use that equation,
![c_s = \frac{4\alpha}{\sqrt{M^2_{\infty}-1}}=\frac{4(0.087)}{\sqrt{2^2-1}}=0.2](https://tex.z-dn.net/?f=c_s%20%3D%20%5Cfrac%7B4%5Calpha%7D%7B%5Csqrt%7BM%5E2_%7B%5Cinfty%7D-1%7D%7D%3D%5Cfrac%7B4%280.087%29%7D%7B%5Csqrt%7B2%5E2-1%7D%7D%3D0.2)
D. It is the same energy but now pushing twice as much, so it would be half as fast so 1 m/s