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myrzilka [38]
3 years ago
5

A 5 kg fish swimming 2 m/s swallows an absent minded 1 kg fish swimming toward it at a velocity that brings both fish to a halt

immediately after lunch. What is the velocity v of the smaller fish before lunch?
Physics
1 answer:
Gelneren [198K]3 years ago
8 0

Answer:

v = 10 m/s

Explanation:

given,

Mass of large fish, M = 5 Kg

speed of swimming, v' = 2 m/s

mass of small fish, m = 1 kg

speed of the fish = v

using conservation of momentum

m v + M v' = M u' + m u

final speed of both the speed is zero.

- 1 x v + 5 x 2  = 0

negative sign is used because small fish is moving in opposite direction.

now,

v = 10 m/s

hence, the speed of the small fish is equal to 10 m/s.

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