A 5 kg fish swimming 2 m/s swallows an absent minded 1 kg fish swimming toward it at a velocity that brings both fish to a halt
1 answer:
You might be interested in
A)
The energy stored in a capacitor is given by:
where
Q is the charge stored
C is the capacitance
The capacitance of a parallel-plate capacitor is
where
is the vacuum permittivity
is the area of each plate
is the distance between the plates
Substituting,
The charge stored on the capacitor is
So, the energy stored is
B)
This time, the separation between the plates is
d = 1.7 mm = 0.0017 m
So, the new capacitance is
And so, the new energy stored is
C)
Energy must be conserved, so the difference between the initial energy of the capacitor and its final energy is just equal to the work done to increase the separation between the two plates from 1.5 mm to 1.7 mm (in fact, the two plates of the capacitor attract each other since they have opposite charge, so work must be done in order to increase their separation)
Given that,
Time = 0.5 s
Acceleration = 10 m/s²
(I). We need to calculate the speed of apple
Using equation of motion
Where, v = speed
u = initial speed
a = acceleration
t = time
Put the value into the formula
(III). We need to calculate the height of the branch of the tree from the ground
Using equation of motion
Put the value into the formula
(II). We need to calculate the average velocity during 0.5 sec
Using formula of average velocity
Where, = final position
= initial position
Put the value into the formula
Hence, (I). The speed of apple is 5 m/s.
(II). The average velocity during 0.5 sec is 2.5 m/s
(III). The height of the branch of the tree from the ground is 1.25 m.