Answer:
Heat required to melt 1 lb of ice is 151.469 KJ
Explanation:
We have given mass of ice = 1 lb
We know that 1 lb = 0.4535 kg
Latent heat of fusion for ice =334 KJ/kg
Amount if heat for fusion of ice is given by
, here m is mass of ice and L is latent heat of fusion
So heat
So heat required to melt 1 lb of ice is equal to 151.469 KJ
The correct answer to the question is :
EXPLANATION :
As per the question, the specific heat of gold is given as c =
The heat given to the gold dQ = 195 J
The mass of the gold is given as m = 15 gram.
We are asked to calculate the change in temperature.
Let the change in temperature is dT.
We know that dQ = mcdT
[ANS]
Hence, the change in temperature is 100 degree celsius.
Answer:
a)
b)
Explanation:
Let's find the radius of the circumference first. We know that bob follows a circular path of circumference 0.94 m, it means that the perimeter is 0.94 m.
The perimeter of a circunference is:
Now, we need to find the angle of the pendulum from vertical.
Let's apply Newton's second law to find the tension.
We use centripetal acceleration here, because we have a circular motion.
The vertical equation of motion will be:
(1)
The horizontal equation of motion will be:
(2)
a) We can find T usinf the equation (1):
We can find the angular velocity (ω) from the equation (2):
b) We know that the period is T=2π/ω, therefore:
I hope it helps you!