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Iteru [2.4K]
3 years ago
10

Right triangle EFG and right triangle EHG overlap as shown below. Angle HEG measures 35° and angle FGE measures 30°.

Mathematics
1 answer:
lesantik [10]3 years ago
3 0

Given:

Triangle EFG and EHG are two right triangles.

m\angle HEG=35^\circ

m\angle FGE=30^\circ

To find:

The values of x and y.

Solution:

In triangle EFG,

m\angle EFG+m\angle FGE+m\angle FEG=180^\circ        [Angle sum property]

90^\circ+30^\circ+(x+35)^\circ=180^\circ

(x+155)^\circ=180^\circ

x+155=180

x=180-155

x=25

In triangle EHG,

m\angle EHG+m\angle HEG+m\angle EGH=180^\circ        [Angle sum property]

90^\circ+35^\circ+(y+30)^\circ=180^\circ

(y+155)^\circ=180^\circ

y+155=180

y=180-155

y=25

Therefore, the value of x is 25 and the value of y is also 25.

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oksano4ka [1.4K]

Answer:

t=\frac{55.82-56}{\frac{0.77}{\sqrt{49}}}=-1.636      

Step-by-step explanation:

Data given and notation      

\bar X=55.82 represent the sample mean

s=0.77 represent the standard deviation for the sample      

n=49 sample size      

\mu_o =56 represent the value that we want to test    

\alpha represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean is less than 56, the system of hypothesis would be:      

Null hypothesis:\mu \geq 56      

Alternative hypothesis:\mu < 56      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{55.82-56}{\frac{0.77}{\sqrt{49}}}=-1.636      

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We have been given that on a coordinate plane a line with negative slope passes through points (0,1) and (1,-1). We are asked to find the rate of the change of the function.

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