Answer:
y = -1/2
Step-by-step explanation:
−7⋅
Answer:
9.3
Step-by-step explanation:
2/.214
QUESTION:- EVALUATE THE EXPRESSION
EXPRESSION:-
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2}](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20)
<h3>ANSWER-></h3>
![{( \sqrt[6]{27 {a}^{3} {b}^{4} } )}^{2} \\ {( {27 {a}^{3} {b}^{4} } )}^{ \frac{2}{6} } \\ {({27 {a}^{3} {b}^{4} } )}^{ \frac{ \cancel{2}}{ \cancel6 {}^{ \: 3} } } \\ {(27)}^{ \frac{1}{3} } {a}^{ \frac{3}{3} } {b}^{ \frac{4}{3} } \\{(3)}^{ \frac{ \cancel3}{ \cancel3} } {a}^{ \frac{ \cancel3}{ \cancel3} } {b}^{\frac{3 + 1}{3} } \\3a {b}^{ \frac{ \cancel3}{ \cancel3} } {b}^{ \frac{1}{3} }](https://tex.z-dn.net/?f=%7B%28%20%5Csqrt%5B6%5D%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B2%7D%20%20%5C%5C%20%7B%28%20%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B2%7D%7B6%7D%20%7D%20%20%5C%5C%20%7B%28%7B27%20%7Ba%7D%5E%7B3%7D%20%20%7Bb%7D%5E%7B4%7D%20%7D%20%29%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel%7B2%7D%7D%7B%20%5Ccancel6%20%7B%7D%5E%7B%20%5C%3A%20%203%7D%20%7D%20%7D%20%5C%5C%20%7B%2827%29%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B3%7D%7B3%7D%20%7D%20%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20%5C%5C%7B%283%29%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Ba%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Bb%7D%5E%7B%5Cfrac%7B3%20%2B%201%7D%7B3%7D%20%7D%20%5C%5C3a%20%7Bb%7D%5E%7B%20%5Cfrac%7B%20%5Ccancel3%7D%7B%20%5Ccancel3%7D%20%7D%20%20%7Bb%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20)
![\\ ANSWER->3ab \sqrt[3]{b} \: \: \: \: \: or \: \: 3a {b}^{ \frac{4}{3} }](https://tex.z-dn.net/?f=%20%5C%5C%20ANSWER-%3E3ab%20%5Csqrt%5B3%5D%7Bb%7D%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20or%20%5C%3A%20%5C%3A%203a%20%7Bb%7D%5E%7B%20%5Cfrac%7B4%7D%7B3%7D%20%7D%20)
Answer:
The answer to your question is Area = 6 u²
Step-by-step explanation:
Process
To find the area of the picture divide the figure between a square and a right triangle, determine the area of each figure and finally add them up.
1.- Calculate the area of the square
Area = side x side
= 2 x 2
= 4 u²
2.- Calculate the area of the triangle
Area = base x height / 2
base = 2 height = 2
Area = 2 x 2 /2
Area = 2 u₂
3.- Total area
Area = 4 + 2
= 6 u²
Answer:
Ooh man, this was back in geometry I think, I think the answer is 4 if my calculations are correct.
i think the bigger side is twice the size of the smaller side, so 2 times 8 is 16,
16 = 5x - 4
x = 4
