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snow_tiger [21]
3 years ago
8

Please i need help on this

Mathematics
2 answers:
fenix001 [56]3 years ago
8 0
For the question you want to:

For each book go across the graph how ever many pages there are and up how ever many words there are, then place a dot.
Maksim231197 [3]3 years ago
3 0
Yep listen to them ^
You might be interested in
How many 1/ 4-inch cubes does it take to fill a box with width 2 1/ 4 inches, length 2 1/ 2 inches, and height 1 3/ 4 inches?
lys-0071 [83]

Answer:

630.

Step-by-step explanation:

<u>Given the following data;</u>

Dimensions for cube = ¼ inches

Volume \; of \; cube = \frac {1}{4} * \frac {1}{4} * \frac {1}{4}

Volume = 1/64 cubic inches.

For rectangular box;

Length = 2½ = 5/2 inches.

Width = 2¼ = 9/4 inches.

Height = 1¾ = 7/4 inches.

Volume \; of \; cube = \frac {5}{2} * \frac {9}{4} * \frac {7}{4}  

Volume = 315/32 inches

Therefore, to find the amount of cubes;

Number \; of \; cubes = \frac {Volume \; of \; box}{Volume \; of \; cube}

Substituting into the equation, we have;

Number \; of \; cubes = \frac {\frac {315}{32}} {\frac {1}{64}}

Number \; of \; cubes = \frac {315}{32} * 64

Number \; of \; cubes = 315 * 2

Number of cubes = 630

6 0
3 years ago
Read 2 more answers
Please can you simplify -x+2z+x+2y
slavikrds [6]

Answer:

2y + 2z

Step-by-step explanation:

-x + 2z + x + 2y

= (-1 + 1)x + 2y + 2z

= 2y + 2z

Hope this helped!

3 0
3 years ago
Could anyone help me with this
Romashka-Z-Leto [24]
The answer is 154

This is because you add all the sides

33+56+65=154
8 0
4 years ago
The length of a photograph is 3cm less than twice the width. The area is 54cm^2. Find the dimensions of the photograph.
REY [17]
W= width
l= length= 2w-3

Area= length * width
A= lw
substitute l=2w-3 for l
54= (2w-3)(w)
54= 2w^2 - 3w
subtract 54 from both sides
0= 2w^2 - 3w - 54
factor the polynomial
0= (2w + 9)(w - 6)

Set each set of parentheses equal
to 0 and solve for width.

0=2w+9
-9=2w
-4.5= w NEGATIVE VALUE

0=w-6
6 cm=w

-4.5 is not the answer because it has a negative value. You cannot have a negative side of a photograph. So substitute 6 in to find length.

length= 2w-3
l= 2(6)-3
l= 12-3
l= 9 cm

CHECK:
w= 6cm
l= 9cm
Area= length * width
54= 6*9
54= 54

ANSWER: width= 6cm; length= 9cm

Hope this helps! :)
4 0
3 years ago
What is the y-intercept of the line perpendicular to the line y = 4/3x + 1 that includes the point (4, 1)?
Alexeev081 [22]

\bf y=\stackrel{\downarrow }{\cfrac{4}{3}}x+1\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{4}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{4}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{4}}}

so then, we know this line has a slope of -3/4 and runs through (4 , 1)

\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{1})~\hspace{10em} slope = m\implies -\cfrac{3}{4} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-1=-\cfrac{3}{4}(x-4)\implies y-1=-\cfrac{3}{4}x+3

\bf y=-\cfrac{3}{4}x\stackrel{\downarrow }{+4}\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hfill \stackrel{\textit{y-intercept}}{(0,4)}

3 0
3 years ago
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