If you want some one to answer this you need a picture more info for people to go off of
assuming the scale is by 1,
a) the slope is rise/run so it rises 3 units and moves 4 units right therefore the slope is 3/4
b) the y intercept is where the line crosses the y axis so by looking at the graph you can tell that the y int is 1
c) and the equation is made up of the slope and the y intercept: y= 3/4x + 1
Answer:
213 books
Step-by-step explanation:
Paper books = $1.45 each
$ 1.45 = 1 paper book
$ 1 = 1/1.45 paper book
$98.6 = 98.6/1.45 paper books
$ 98.6 = 68 paper books
Hardback books = $ 2.25 each
$2.25 = 1 Hardbook
$1 = 1/2.25 hardbook
$ 328.10 = 328.10/2.25 hardbooks
$ 328.10 = 145.822 hard books
Number of books cannot be a decimal number, so the value has to be estimated to a nearer whole number.
$ 328.10 = 145 hard books
Total number of books bought = (145 + 68)books= 213 books (Answer)
Answer:
45 minutes
Step-by-step explanation:
At 30 mph for 1/4 hour, Peter has a 7.5 mile head start. After he leaves, Mitchell closes that gap at the rate of 40-30 = 10 miles per hour. It will take him ...
t = d/s
t = (7.5 mi)/(10 mi/h) = 0.75 h
to catch Peter.
Mitchell will catch Peter in 45 minutes.
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<em>Alternate Solution</em>
Another way to look at it is that Mitchell's 10 mph advantage is 1/3 of Peter's speed, so it will take 1/(1/3) = 3 times the period of Peter's head start:
3 × 15 minutes = 45 minutes . . . for Mitchell to catch Peter
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You can write equations involving time and distance and see where the distances traveled become the same. You need to be careful choosing the time reference, since you're concerned with Mitchell's travel time. I personally prefer to work "head start" problems by considering the differences in time and speed, as above. This is where you end up using the equations approach, anyway.
