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coldgirl [10]
3 years ago
13

Select the true statement for the graph

Mathematics
2 answers:
salantis [7]3 years ago
5 0

Answer:

C srry if wrong

Step-by-step explanation:

AfilCa [17]3 years ago
5 0
It’s c hope I helped
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45min/hour = ___ ft/seconds
emmasim [6.3K]
The answer to your question is 45 miles / 1 hour * 5280 feet / 1 mile * 1 hour / 3660 seconds = 45 * 5280 * 1 / 1 * 1 * 3660 = 2737600 feet / 3660 second = 64.918
6 0
4 years ago
What is the degree of the polynomial given below?<br> F(x) - 2x3 - x2 +5x - 3
Anna71 [15]

Answer:

3

Step-by-step explanation:

3 is the degree of polynomial f(x) = -2x^3-x^2+5x-3

=> Degree of the polynomial is the highest power/exponent contained by the variable in the expression.

6 0
3 years ago
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A tank holds 300 gallons of water and 100 pounds of salt. A saline solution with concentration 1 lb salt/gal is added at a rate
Shkiper50 [21]

The amount of salt in the tank changes with rate according to

Q'(t)=\left(1\dfrac{\rm lb}{\rm gal}\right)\left(4\dfrac{\rm gal}{\rm min}\right)-\left(\dfrac{Q(t)}{300+(4-1)t}\dfrac{\rm lb}{\rm gal}\right)\left(1\dfrac{\rm gal}{\rm min}\right)

\implies Q'+\dfrac Q{300+3t}=4

which is a linear ODE in Q(t). Multiplying both sides by (300+3t)^{1/3} gives

(300+3t)^{1/3}Q'+(300+3t)^{-2/3}Q=4(300+3t)^{1/3}

so that the left side condenses into the derivative of a product,

\big((300+3t)^{1/3}Q\big)'=4(300+3t)^{1/3}

Integrate both sides and solve for Q(t) to get

(300+3t)^{1/3}Q=(300+3t)^{4/3}+C

\implies Q(t)=300+3t+C(300+3t)^{-1/3}

Given that Q(0)=100, we find

100=300+C\cdot300^{-1/3}\implies C=-200\cdot300^{1/3}

and we get the particular solution

Q(t)=300+3t-200\cdot300^{1/3}(300+3t)^{-1/3}

\boxed{Q(t)=300+3t-2\cdot100^{4/3}(100+t)^{-1/3}}

5 0
3 years ago
Which point is on the graph of f(x) = 3 x 5^x?
Harlamova29_29 [7]

Answer:

C

Step-by-step explanation:

To determine which point lies on the graph, substitute the x-coordinate into f(x) and if the value is equal to the y-coordinate then the point is on the graph

A (15, 1)

f(15) = 3 × 5^{15} ≠ 1 ← not on graph

B (0, 15)

f(0) = 3 × 5^{0} = 3 × 1 = 3 ≠ 15 ← not on graph

C (1, 15)

f(1) = 3 × 5^{1} = 3 × 5 = 15 ← lies on graph

D (0, 0)

f(0) = 3 × 5^{0} = 3 × 1 = 3 ≠ 0 ← not on graph



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4 years ago
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1/4x%%%%%%%%%%%%%%%%%%%%%%%%%
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