All categories

2 years ago

What are the possible values for m and n

Mathematics

1 answer:

Reika [66]2 years ago

5 0

Answer:

m=4

n=-6

The above is just a possible value you can come up with your own :D.

See below for an explanation.

Step-by-step explanation:

Here you are going to really know the exponent rules. But in jest, you basically need to know that m+n=-2 due to exponent rules.

So?

An example would be

m=4

n=-6

Why?

Because 4-6=-2!

You might be interested in

Find thd <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bdy%7D%7Bdx%7D" id="TexFormula1" title="\frac{dy}{dx}" alt="\frac{dy}{dx}" a

NARA [144]

$x^3y^2+\sin(x\ln y)+e^{xy}=0$

Differentiate both sides, treating $y$ as a function of $x$ . Let's take it one term at a time.

Power, product and chain rules:

$\dfrac{\mathrm d(x^3y^2)}{\mathrm dx}=\dfrac{\mathrm d(x^3)}{\mathrm dx}y^2+x^3\dfrac{\mathrm d(y^2)}{\mathrm dx}$

$=3x^2y^2+x^3(2y)\dfrac{\mathrm dy}{\mathrm dx}$

$=3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(\sin(x\ln y)}{\mathrm dx}=\cos(x\ln y)\dfrac{\mathrm d(x\ln y)}{\mathrm dx}$

$=\cos(x\ln y)\left(\dfrac{\mathrm d(x)}{\mathrm dx}\ln y+x\dfrac{\mathrm d(\ln y)}{\mathrm dx}\right)$

$=\cos(x\ln y)\left(\ln y+\dfrac1y\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}$

Product and chain rules:

$\dfrac{\mathrm d(e^{xy})}{\mathrm dx}=e^{xy}\dfrac{\mathrm d(xy)}{\mathrm dx}$

$=e^{xy}\left(\dfrac{\mathrm d(x)}{\mathrm dx}y+x\dfrac{\mathrm d(y)}{\mathrm dx}\right)$

$=e^{xy}\left(y+x\dfrac{\mathrm dy}{\mathrm dx}\right)$

$=ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}$

The derivative of 0 is, of course, 0. So we have, upon differentiating everything,

$3x^2y^2+6x^3y\dfrac{\mathrm dy}{\mathrm dx}+\cos(x\ln y)\ln y+\dfrac{\cos(x\ln y)}y\dfrac{\mathrm dy}{\mathrm dx}+ye^{xy}+xe^{xy}\dfrac{\mathrm dy}{\mathrm dx}=0$

Isolate the derivative, and solve for it:

$\left(6x^3y+\dfrac{\cos(x\ln y)}y+xe^{xy}\right)\dfrac{\mathrm dy}{\mathrm dx}=-\left(3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}\right)$

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^2+\cos(x\ln y)\ln y-ye^{xy}}{6x^3y+\frac{\cos(x\ln y)}y+xe^{xy}}$

(See comment below; all the 6s should be 2s)

We can simplify this a bit by multiplying the numerator and denominator by $y$ to get rid of that fraction in the denominator.

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x^2y^3+y\cos(x\ln y)\ln y-y^2e^{xy}}{6x^3y^2+\cos(x\ln y)+xye^{xy}}$

3 0

2 years ago

Three ballet dancers are positioned on stage. Greta is straight behind Bryan and directly left of Alice. If Bryan and Greta are

Neko [114]

Answer:

Step-by-step explanation:

4 0

2 years ago

There are three options for fans purchasing a band's new release CD. They can purchase the CD, a premium CD bundle, or a deluxe

cluponka [151]

Answer:

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

Step-by-step explanation:

Let c represents the number of CD's

Let d represents the number of deluxe bundles

Let p represents the number of premium bundles.

Now according to the given statement:

c = $15

d = c+2p =

d = 15+2p --------equation 1

455c+87p+35d = $12,845 --------equation 2

Now substitute the value of d in equation 2 to find the value of p

455c+87p+35d = $12,845

455(15)+87p+35(15+2p) = $12,845

6825+87p+525+70p=$12,845

Now combine the like terms:

6825+157p+525 = $12,845

Now shift all the like terms to the R.H.S

157p= 12845-6825-525

157p = 5495

Divide both sides by 157

157p/157 = 5495/157

p = 35

Now substitute the value p =35 in equation 1.

d = 15+ 2p

d = 15+2(35)

d = 15+70

d = 85

Therefore we have found that,

The price of CD's = $15

The price of deluxe bundles = $85

The price of premium bundles. = $ 35 ....

4 0

3 years ago

The rectangular model is made up of squares. Each square is of equal size.

IrinaK [193]

H 45%
you would add up the number of shaded squares and divide that by the total number of squares

6 0

2 years ago

Read 2 more answers

-Dominant- [34]

Answer:

G. 78.5 / π

{ i hope this helps :) i'm sorry if its wrong }

8 0

2 years ago