All categories

1 year ago

In febuary, john has $1000 in his account. in may, he had 2600. what is the rate of change?

Mathematics

1 answer:

sergiy2304 [10]1 year ago

5 0

Answer:

866.7 each month

Step-by-step explanation:

what you would do is count how many months are in between which is 3 and then you would divide 2600 by 3 and get 866.7 so the rate of change is 866.7 each month

please mark brainliest

You might be interested in

Susan worked 5 out of 8 hours during the day what percentage of the day does she work

Aleksandr-060686 [28]

5/8 * 125/125 = 625/1,000 = 0.625
62.5 percent
Solution: 62.5%

4 0

2 years ago

Read 2 more answers

Find the scale factor A. 3.5 B. 3/5 C. 35

Serhud [2]

Answer:

3.5

Step-by-step explanation:

35/10 = 3.5

4 0

2 years ago

Multiply the polynomial 2x(x−3) A)2x^2-6x B)2x-6 C)x^2-6

dlinn [17]

Multiply 2x by each term in the parentheses:

2x(x - 3)
2x^2 - 6x

Answer:
2x^2 - 6x

6 0

2 years ago

Please show work thank you

Ne4ueva [31]

Answer: 70 mph

Step-by-step explanation:

8 0

2 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

2 years ago