Question

Find the surface area of the space figure represented by the net

Answer 1

Im pretty the answer is 164 cm. not 124 cm.!!!

14 + 14 + 56 + 40 + 40 = 164

check in a calculator

Answer 2

Answer:

D. 164 $cm^{2}$

Step-by-step explanation:

We have that the net includes three rectangles and two triangles.

So, the surface area of the net = area of 3 rectangles + area of 2 triangles.

Now, there are two rectangles having length 8 cm and width 5 cm.

So, the area of this rectangle = length × breadth = 8 × 5 = 40 $cm^{2}$

Also, one rectangle has length 8 cm and width 7 cm.

So, the area of this rectangle = length × breadth = 8 × 7 = 56 $cm^{2}$

Now, as there are two triangles having base length 7 cm and height 4 cm.

So, area of both of these triangles = $2 \times \frac{1}{2} \times b \times h$ = $2 \times\frac{1}{2} \times 7 \times 4$ =28 $cm^{2}$.

Therefore, the final area of the net = 40 + 40 + 56 + 28 = 164 $cm^{2}$.