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Aleonysh [2.5K]

2 years ago

7

to checkt the accuracy of a new method, a standard copper alloy containing 23.24%Cu was analyzed and calculated to contain 23.17

%. calculate the relative error of the method sin parts per thousand

1 answer:

tekilochka [14]2 years ago

3 0

Answer:

23.24%_23.17%

10%×1000

10/100×1000=

100

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Answer:

Low energy waves have <u>a long wavelength.</u>

Explanation:

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Pressure gauge at the top of a vertical oil well registers 140 bars. The oil well is 6000 m deep and filled with natural gas dow

andreyandreev [35.5K]

Explanation:

(a) The given data is as follows.

Pressure on top ( $P_{o}$ ) = 140 bar = $1.4 \times 10^{7} Pa$ (as 1 bar = $10^{5}$ )

Temperature = $15^{o}C$ = (15 + 273) K = 288 K

Density of gas = $\frac{PM}{ZRT}$

$\frac{dP}{dZ} = \rho \times g$

$\frac{dP}{dZ} = \int \frac{PM}{ZRT}$

$\int_{P_{o}}^{P_{1}} \frac{dP}{dZ} = \frac{Mg}{ZRT} \int_{0}^{4700} dZ$

$ln (\frac{P_{1}}{P_{o}}) = \frac{18.9 \times 10^{-3} \times 9.81 \times 4700 m}{0.80 \times 8.314 J/mol K \times 288 K}$

= 0.4548

$P_{1} = P_{o} \times e^{0.4548}$

= $1.4 \times 10^{7} Pa \times 1.5797$

= $2.206 \times 10^{7} Pa$

Hence, pressure at the natural gas-oil interface is $2.206 \times 10^{7} Pa$ .

(b) At the bottom of the tank,

$P_{2} = P_{1} + \rho \times g \times h$

= 2.206 \times 10^{7} Pa + 700 \times 9.81 \times (6000 - 4700)[/tex]

= $309.8 \times 10^{5} Pa$

= 309.8 bar

Hence, at the bottom of the well at $15^{o}C$ pressure is 309.8 bar.

6 0

3 years ago

What are the different acid bases

Alex

Answer:

different acids include acetic acid,lactic acid,tartaric acids DNA(deoxyribonucliec acid) .

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6. According to Crystal Field Theory, what should be the color of an aqueous solution of the ion [Y(H2O)6]3

UkoKoshka [18]

Answer:

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Explanation:

We know that Y^3+ has the electronic configuration of;

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3 years ago