The molar mass of gas = 238.29 g/mol
<h3>Further explanation</h3>
Given
mass = 81.5 g
P=1.75 atm
V=4.92 L
T=307 K
Required
molar mass
Solution
The gas equation can be written
So the equation becomes :
Input the value :
Answer:
a. 0.119mol Kr
Explanation:
To solve this problem, we must understand that;
Mass = number of moles x molar mass
Molar mass of Kr = 83.3g/mol
Ar = 40g/mol
He = 4g/mol
Ne = 20.18g/mol
a0.119 mol Kr mass = 0.119 x 83.3 = 9.9g
b 0.400 mol Ar mass = 0.4 x 40 = 16g
C 1.25 mol He mass = 1.25 x 4 = 5g
d 2.02 mol Ne mass = 2.02 x 20.18 = 40.8
Krypton is the answer
Molar mass of CH2NH2COOH - 75
Given mass of CH2NH2COOH - 30
Moles of CH2NH2COOH = Given mass/ Molar mass
moles of CH2NH2COOH = 30/75 = 0.4 mol
One mole of CH2NH2COOH contains 32 gram of oxygen
0.4 mole of CH2NH2COOH will contain = 0.4 × 32= 12.8 g of oxygen
Answer- the mass of oxygen in 30 g of CH2NH2COOH is 12.8 gram!
<h3>
Answer:</h3>
C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)
<h3>
Explanation:</h3>
The balanced chemical equation for the combustion of the hydrocarbon in question is;
C₅H₁₂O(l)+15/2O₂(g)→5CO₂(g)+6H₂O(l)
- A balanced chemical equation is one in which the number of atoms of each element is equal on both sides of the equation.
- Reactant side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
- Product side has; 5 carbon atoms, 12 hydrogen atoms and 16 Oxygen atoms
- An equation is balanced by putting appropriate coefficients on reactants and products involved in the reaction.
- An equation is balanced so as to obey the law of conservation of mass.
