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ziro4ka [17]
3 years ago
9

Write the symbol of another isotope of lead with 132 neutrons.

Chemistry
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

Pb^+7

Explanation:

I placed the carrot there to signify the +7 is supposed to be small. It is plus seven because seven nuetrons are added

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What is the pH of 0.000134 M solution of HCI?
mafiozo [28]

Answer: The pH will be 3.87

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,

1 mole of HCl gives 1 mole of H^+

Thus 0.000134 moles of HCl gives =\frac{1}{1}\times 0.000134=0.0001342 moles of H^+

Putting in the values:

pH=-\log[0.000134]

pH=3.87

Thus the pH will be 3.87

5 0
3 years ago
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8. Which of the following compounds is an ionic compound? (metal)
fomenos
The answer is b, because all of the other compounds are covelent
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3 years ago
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Why is water considered the greatest solvent on earth
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1) H2O is able to dissolve both polar molecules and non polar ones
2) due to its extreme polarity it can even dissolve some I onic compounds
3 the h2o molecule itself is small in size
6 0
3 years ago
Hot air balloons work due to a current moving heat energy around within the balloon. which heat energy transfer process is happe
miv72 [106K]

Answer:

Convection.

Explanation:

Why? This transfer of heat energy away from the ground by the vertical movement of air is called "free convection" or "natural convection." A hot air balloon rises because warmer air is less dense than cool air.                                                (plz brainlyest)

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3 years ago
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The normal boiling point of bromine is 58.8°C, and its enthalpy of vaporization is 30.91 kJ/mol. What is the approximate vapor p
saul85 [17]

Answer : The vapor pressure of bromine at 10.0^oC is 0.1448 atm.

Explanation :

The Clausius- Clapeyron equation is :

\ln (\frac{P_2}{P_1})=\frac{\Delta H_{vap}}{R}\times (\frac{1}{T_1}-\frac{1}{T_2})

where,

P_1 = vapor pressure of bromine at 10.0^oC = ?

P_2 = vapor pressure of propane at normal boiling point = 1 atm

T_1 = temperature of propane = 10.0^oC=273+10.0=283.0K

T_2 = normal boiling point of bromine = 58.8^oC=273+58.8=331.8K

\Delta H_{vap} = heat of vaporization = 30.91 kJ/mole = 30910 J/mole

R = universal constant = 8.314 J/K.mole

Now put all the given values in the above formula, we get:

\ln (\frac{1atm}{P_1})=\frac{30910J/mole}{8.314J/K.mole}\times (\frac{1}{283.0K}-\frac{1}{331.8K})

P_1=0.1448atm

Hence, the vapor pressure of bromine at 10.0^oC is 0.1448 atm.

4 0
3 years ago
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