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ziro4ka [17]
3 years ago
9

Write the symbol of another isotope of lead with 132 neutrons.

Chemistry
1 answer:
Ivahew [28]3 years ago
5 0

Answer:

Pb^+7

Explanation:

I placed the carrot there to signify the +7 is supposed to be small. It is plus seven because seven nuetrons are added

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An atom of potassium loses one electron. what does it become a negative potassium, positive potassium
STALIN [3.7K]
Yes, K+ is<span> a </span>potassium<span> ion, and Mg</span>2+ is<span> a magnesium ion. But However, when non-metallic elements gain the </span>electrons<span> to form anions, Yes the end of their name </span>is<span> changed to “-ide.” and yes the example, a fluorine </span>atom<span> gains </span>one electron<span> to </span>become<span> a yes fluoride ion (F</span>-<span>) sooo yeessyes</span>
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3 years ago
Part 1: Describe the mass and surface temperature of the supergiant stars.
Julli [10]
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part 2 :-   HR diagram : hertzsprung -Russel diagram ( attached below)

3 0
3 years ago
Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife​
yuradex [85]

Answer:

\boxed{\text{2408 min}}

Explanation:

The integrated rate law for radioactive decay is

\ln\dfrac{N_{0}}{N_{t}} = kt

1. Calculate the decay constant

\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\

2. Calculate the half-life

t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}

8 0
3 years ago
2.00 moles of an ideal gas was found to occupy a volume of 17.4L at a pressure of 3.00 atm and at a temperature of 45 C. Calulat
lidiya [134]

Answer:

0.082 atm L mol^{-1} K^{-1}

Explanation:

The pressure, the volume and the temperature of an ideal gas are related to each other by the equation of state:

pV=nRT

where

p is the pressure of the gas

V is the volume of the gas

n is the number of moles

R is the gas constant

T is the absolute temperature

For the gas in this problem:

n = 2.00 mol is the number of moles

V = 17.4 L is the gas volume

p = 3.00 atm is the gas pressure

T=45C+273=318 K is the absolute temperature

Solving for R, we find the gas constant:

R=\frac{pV}{nT}=\frac{(3.00)(17.4)}{(2.00)(318)}=0.082 atm L mol^{-1} K^{-1}

5 0
3 years ago
For the following reaction, 7.72 grams of nitrogen gas are allowed to react with 4.86 grams of oxygen gas . nitrogen(g) oxygen(g
inn [45]
There could be a big maximum amount or small, either works
7 0
3 years ago
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