He thought they needed to be idolized
The Nitrogen (N) will have the greatest attraction for the chlorine electrons.
Answer: A) N
Explanation
The tendency or the ability to attract electrons is termed as electronegativity.
The electronegativity tend to increase from left to right in the periods and bottom to top in the groups of the periodic table. So it is known that the halogen group consists of the most electronegative elements.
Though chlorine has high electronegativity of 3.16, the electrons of chlorine can be attracted by other electronegative elements provided that their electronegativity should be in the range of the electronegativity of Cl.
So among the elements given, Nitrogen (N) has an electronegativity of 3.04, Phosphor (P) has an electronegativity of 2.19 and Arsenide electronegativity is 2.18.
Thus it can be seen that the electronegativity is maximum for Nitrogen among the three elements so it should have the greatest tendency to attract Cl electrons.
Answer:
Production of Citric Acid
It is an organic carboxylic acid and can be extracted from the juice of citrus fruits by adding calcium oxide to form calcium citrate, which is an insoluble precipitate that can be collected by filtration; the citric acid can be recovered from its calcium salt by adding sulfuric acid.
Explanation:
Answer:
24.5 moles of mercury are produced
Explanation:
The descomposition of mercury(II) oxide, occurs as follows:
2HgO → 2Hg + O₂
<em>Where 2 moles of HgO produce 2 moles of Hg</em>
<em />
In other words, the ratio of descomposition of HgO/Hg is 2/2 = 1:1
That means, if 24.5 moles of mercury(II) oxide descompose:
<h3>24.5 moles of mercury are produced</h3>
4.14x10^-3 per minute
First, calculate how many atoms of Cu-61 we initially started with by
multiplying the number of moles by Avogadro's number.
7.85x10^-5 * 6.0221409x10^23 = 4.7273806065x10^19
Now calculate how many atoms are left after 90.0 minutes by subtracting the
number of decays (as indicated by the positron emission) from the original
count.
4.7273806065x10^19 - 1.47x10^19 = 3.2573806065x10^19
Determine the percentage of Cu-61 left.
3.2573806065x10^19/4.7273806065x10^19 = 0.6890455577
The formula for decay is:
N = N0 e^(-λt)
where
N = amount left after time t
N0 = amount starting with at time 0
λ = decay constant
t = time
Solving for λ:
N = N0 e^(-λt)
N/N0 = e^(-λt)
ln(N/N0) = -λt
-ln(N/N0)/t = λ
Now substitute the known values and solve:
-ln(N/N0)/t = λ
-ln(0.6890455577)/90m = λ
0.372447889/90m = λ
0.372447889/90m = λ
0.00413830987 1/m = λ
Rounding to 3 significant figures gives 4.14x10^-3 per minute as the decay
constant.
