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ivanzaharov [21]
2 years ago
14

Find the common ratio for the geometric sequence defined by the formula: an=40(2‾√)n−1 a n = 40 ( 2 ) n − 1

Mathematics
1 answer:
WITCHER [35]2 years ago
4 0

The ratio of the geometric sequence 402^{n-1} is 2.

Given that geometric sequence is 40*2^{n-1} and we have to find the common ratio of all the terms.

Geometric sequence is a sequence in which all the terms have a common ratio.

Nth termof a GP is ar^{n-1} in which a is first term and r is common ratio.

Geometric sequence=40*2^{n-1}

We have to first find the first term, second term and third term of a geometric progression.

First term=40*2^{1-1}

=40*2^{0}

=40*1

=40

Second term=40*2^{2-1}

=40*2^{1}

=40*2

=80

Third term=40*2^{3-1}

=40*2^{2}

=40*4

=160

Ratio of first two terms=80/40=2

Ratio of next two terms=160/80=2

Hence the common ratio of geometric sequence is 2.

Learn more about geometric progression at brainly.com/question/12006112

#SPJ1

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The ordered pair that is the best estimate for the solution of the system of equations is (7, 1/2)

The given system of equations is:

y=-\frac{1}{2}x + 4.......................(1)\\\\y = \frac{1}{2}x-3..........................(2)

Equate equations (1) and (2)

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Solve for x in the equation above

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Substitute x = 7 into equation (1)

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