<span> There are 97.2 mol of O in 10.8 mol of Fe(NO3)3</span>
Answer:
0.85 mol/L.
Explanation:
- Molarity is defined as the no. of moles of solute dissolved in a liter of the solution.
<em>M = (no. of moles of solute)/(Volume of the solution (L))</em>
no. of moles of calcium phosphate = 2.125 mol.
Volume of the solution = 2.5 L.
<em>∴ M of calcium phosphate</em> = (2.125 mol)/(2.5 L) = <em>0.85 mol/L.</em>
